Php 如何在Zend框架中使用openid测试登录？

我使用openid（例如使用google、myopenid、yahoo）在ZF登录我的webiste。它工作得很好。但我不知道如何为它编写单元测试

例如，我想编写单元测试：

public function testUserLogsSuccessfullyUsingGoogle() {
        // don't know how to dispach/mock that my action
        // will take a user to google, and google will
        // return authentication data (e.g. email)
        // Once user is authenticated by google, 
        // I make Zend_Auth for the user. 
        // 


        $this->asertTrue(Zend_Auth::getInstance()->getIdentity());
}


public function testUserLogsUnSuccessfullyUsingGoogle() {
        // don't know how to dispach/mock that my action
        // will take a user to google, and USER WILL NOT ALLOW
        // for authentication. Then off course I don't make
        // Zend_Auth for the user. 
        // 


        $this->asertFalse(Zend_Auth::getInstance()->getIdentity());
}

---

有人知道怎么嘲笑这个场景吗？也许有人举了一些例子？

您不需要测试Google是否工作和响应（即使它不工作，您也无法修复此问题），也不需要测试Zend_OpenId（已经介绍过了）。您只需要测试自己的代码。因此，存根OpenId响应可能是一个好主意。我不知道你的代码看起来如何，假设你有一个来自Zend参考指南的例子，使用你的Mygoogle\u OpenId\u Consumer类

if (isset($_POST['openid_action']) &&
    $_POST['openid_action'] == "login" &&
    !empty($_POST['openid_identifier'])) {
    $consumer = new Mygoogle_OpenId_Consumer();
    if (!$consumer->login($_POST['openid_identifier'])) {
        $status = "OpenID login failed.";
    }

} else if (isset($_GET['openid_mode'])) {
    if ($_GET['openid_mode'] == "id_res") {
        $consumer = new Mygoogle_OpenId_Consumer();
        if ($consumer->verify($_GET, $id)) {
            $status = "VALID " . htmlspecialchars($id);
       } else {
           $status = "INVALID " . htmlspecialchars($id);
       }
    } else if ($_GET['openid_mode'] == "cancel") {
        $status = "CANCELLED";
    }
} 

在这里，你不想给谷歌打真正的电话，也不想测试Zend_OpenId_消费者，所以我们需要存根Zend_OpenId_消费者。为了能够在您的类中存根它，我们将使用一个适配器，它可以是Zend_OpenId_Consumer，也可以是您的模拟对象

class Mygoogle_OpenId_Consumer extends Zend_OpenId_Consumer
{
    private static $_adapter = null;

    public static function setAdapter($adapter)
    {
        self::$_adapter = $adapter;
    }

    public static function getAdapter()
    {
        if ( empty(self::$_adapter) ) {
            self::$_adapter = new Zend_OpenId_Consumer();
        }

        return self::$_adapter;
    }
.....

最后，在测试中，我们需要创建一个模拟对象，并将其用于存根

private function _stubGoogle($successful = false)
    {
        $adapter = $this->getMock('Mygoogle_OpenId_Consumer', array('login','verify'));

        $httpResponse = $successful?:null;
        $adapter->expects( $this->any() )
               ->method('login')
               ->will( $this->returnValue($httpResponse) );

        $adapter->expects( $this->any() )
               ->method('verify')
               ->will( $this->returnValue($successful) );

        Mygoogle_OpenId_Consumer::setAdapter($adapter);
    }

    public function testUserLogsSuccessfullyUsingGoogle()
    {
        $this->_stubGoogle(true);
        //do whatever you need to test your login action:
        //set and send request, dispatch your action
    }

    public function testUserLogsUnSuccessfullyUsingGoogle()
    {
        $this->_stubGoogle(false);
        ...
    }

---

我没有完整的答案，但您可能想看看ZF中Zend_OpenID组件的单元测试。它可能会给你一些想法。谢谢你的时间。我的代码与中的代码非常相似。