Php 基于关系结果的拉威尔回归数据

PostController.php

$customers = $query->orderBy('id', 'desc')->with('agents:agents.id')->get();
        foreach ($customers as $customer) {
            $customer->calculator = $this->calculator($customer);
        }

        return response()->json($customers, 200 );

function agents()
    {
        return $this->belongsToMany('App\Agent','files','post_id','agent_id');
    }

Post.php

$customers = $query->orderBy('id', 'desc')->with('agents:agents.id')->get();
        foreach ($customers as $customer) {
            $customer->calculator = $this->calculator($customer);
        }

        return response()->json($customers, 200 );

function agents()
    {
        return $this->belongsToMany('App\Agent','files','post_id','agent_id');
    }

此返回权限数据，如下所示：

[{
    "id": 5,
    "hash": "SqB29tkfm1dwGsXp4ZCV",
    "agents": [{
      "id": 1,
      "pivot": {
        "post_id": 5,
        "agent_id": 1
      }
    }]
  },
  {
    "id": 4,
    "hash": "SqH29tkfm1dwGsXp4ZCV",
    "agents": []
  },
  {
    "id": 3,
    "hash": "RqH29tkfm1dwGsXp4ZCV",
    "agents": [{
      "id": 1,
      "pivot": {
        "post_id": 3,
        "agent_id": 1
      }
    }]
  },
  {
    "id": 1,
    "hash": "RqH29tkfm1dwGrXp4ZCV",
    "agents": [{
      "id": 1,
      "pivot": {
        "post_id": 1,
        "agent_id": 1
      }
    }]
  }
]

但我想要的是只返回那些具有空代理的数据，在这种情况下，应该只返回id

4

，因为代理数组是空的。我该怎么做？

试试这个：

$customers = $query->orderBy('id', 'desc')->whereDoesntHave('agents')->get();

如果你想得到没有代理的客户。 阅读更多信息，请尝试以下内容：

$customers = $query->orderBy('id', 'desc')->whereDoesntHave('agents')->get();

如果你想得到没有代理的客户。

---

更多信息请访问

您可以同时使用doesntHave或whereDoesntHave

$customers = $query->orderBy('id', 'desc')->doesntHave('agents')->get();

或

---

您可以同时使用doesntHave或whereDoesntHave

$customers = $query->orderBy('id', 'desc')->doesntHave('agents')->get();

或

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尝试类似于

->whereNull（'agents'）

？尝试类似于

->whereNull（'agents'）

？