slimframework3中的PHP作用域

我认为这可能是一个简单的问题。有人能帮我确定如何最好地访问每个路由器功能中的

$route

变量吗？我正在尝试从一个阵列中添加许多Slim 3路由器功能。以下代码来自/src/routes.php：

<?php
// Standard CRUD Routes (based on templates)

$app->group('/api/v1', function () use ($app) {

  $routes = [
    'calendar' => [
      'table' => 'calendar',
      'prefix' => 'cal',
      'sort' => 'cal_name_orig',
      'fields' => ['cal_name_orig','cal_name_tran','cal_public','cal_color'],
      'permRead' => 1,
      'permWrite' => 1
    ],
    'classroom' => [
      'table' => 'classroom',
      'prefix' => 'room',
      'sort' => 'room_name',
      'fields' => ['room_owner_p_id','room_name','room_common','room_capacity_normal','room_capacity_max','room_current_desks'],
      'permRead' => 1,
      'permWrite' => 1
    ]
  ];

  // register all standard routes using above data
  foreach ($routes as $key => $route) {
    echo "<br><br>ROUTE: $key<br>";
    print_r($route);

    // Add Route: retrieve all records
    $app->get('/' . $key . 's', function ($request, $response, $args) {
      return $this->common->getAll($route['table'], $route['prefix'], $route['sort'], $route['permRead']);
    });

    // Add Route: retrieve specific record
    $app->get('/' . $key . '/[{id}]', function ($request, $response, $args) {
      return $this->common->getById($route['table'], $route['prefix'], $args['id'], $route['permRead']);
    });

    // Add Route: create new record
    $app->put('/' . $key . '/new', function ($request, $response, $args) {
      return $this->common->putNew($route['table'], $route['prefix'], $route['fields'], $route['permWrite']);
    });

    // Add Route: update specific record
    $app->post('/' . $key . '/[{id}]', function ($request, $response, $args) {
      return $this->common->postById($route['table'], $route['prefix'], $args['id'], $route['fields'], $route['permWrite']);
    });

    // Add Route: delete specific record
    $app->delete('/' . $key . '/[{id}]', function ($request, $response, $args) {
      return $this->common->deleteById($route['table'], $route['prefix'], $args['id'], $route['permWrite']);
    });
  }

});

试试看

这非常有效。我已经使用PHP很多年了。。。但从未理解“使用”关键字。因此，这基本上将作用域引入函数？是的，简单地说：“使用”使使用外部变量成为可能：）
 $app->put('/' . $key . '/new', function ($request, $response, $args) use ($route) {