PHP操作未从Python脚本接收Post变量

PHP操作未从Python脚本接收Post变量,php,python,symfony,post,Php,Python,Symfony,Post,我正在使用一个小python脚本发布到我的web服务器。现在,它成功连接,我得到一个错误返回说,我的值不能为空。当我为chrome使用PostMan插件时,我没有收到错误,并且收到了一条成功的返回消息 以下是我在Python中的post函数: temperature = {"tempF": 20, "tempC": 70} def post(): threading.Timer(1800.0, post).start() temperature = read_temp()

我正在使用一个小python脚本发布到我的web服务器。现在,它成功连接,我得到一个错误返回说,我的值不能为空。当我为chrome使用PostMan插件时,我没有收到错误,并且收到了一条成功的返回消息

以下是我在Python中的post函数:

temperature = {"tempF": 20, "tempC": 70}

def post():
    threading.Timer(1800.0, post).start()
    temperature = read_temp()
    data = temperature
    data['room'] = 'Server Room'
    print(data)

    url = 'http://url.to.server'
    query = data 
    res = requests.post(url, data=query)
    print(res.text)
下面是我如何通过PHPsymfony动作引入变量:

public function updateTemperatureAction(Request $request)
{
    $tempF = $request->request->get('tempF');
    $tempC = $request->request->get('tempC');
    $room = $request->request->get('room');

    if(empty($tempF)) throw new \Exception("temperature F is empty");

    if(empty($tempC)) throw new \Exception("temperature C is empty");

    if(empty($room)) throw new \Exception("Room is empty");


    $temperature  = new Temperature();
    $temperature->setTemperatureF($tempF);
    $temperature->setTemperatureC($tempC);
    $temperature->setRoom($room);

    $em = $this->getDoctrine()->getManager();

    $em->persist($temperature);
    $em->flush();

    return new Response($room);
}
这是我的错误:

                        <h1>Oops! Something went wrong.</h1>
    <p>
        The server returned a "<strong>500 Internal Server Error</strong>" error. Please contact the website administrator to address this issue.
    </p>
    <p>
        <small>
            temperature F is empty
        </small>
    </p>

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出现问题是因为我使用的是HTTP而不是HTTPS

请修复Python代码中的缩进。