使用PHP和MySQL创建数据库
好的,我有这个代码:使用PHP和MySQL创建数据库,php,mysql,database,Php,Mysql,Database,好的,我有这个代码: <?php $dbhost = 'localhost'; $dbuser = 'root'; $dbpwd = 'ALLO'; $dbname = 'test'; $conn = mysqli_connect($dbhost, $dbuser, $dbpwd, $dbname); if(! $conn ) { die("\nconn: $conn \nCould not connect: " . mysqli_error($conn)); } echo
<?php
$dbhost = 'localhost';
$dbuser = 'root';
$dbpwd = 'ALLO';
$dbname = 'test';
$conn = mysqli_connect($dbhost, $dbuser, $dbpwd, $dbname);
if(! $conn )
{
die("\nconn: $conn \nCould not connect: " . mysqli_error($conn));
}
echo "\n";
$createtab="CREATE TABLE People(FirstName CHAR(30),LastName CHAR(30),Age INT)";
// Execute query
if (mysqli_query($conn,$createtab))
{
echo "Table created successfully";
}
else
{
echo "Error creating table: " . mysqli_error($conn);
}
echo "\n";
mysqli_query($conn,"INSERT INTO People (FirstName, LastName, Age)
VALUES ('Peter', 'Griffin',35)");
mysqli_query($conn,"INSERT INTO People (FirstName, LastName, Age)
VALUES ('Glenn', 'Quagmire',33)");
mysqli_close($conn)
?>
查看这是否会给您带来任何结果:
SELECT * FROM INFORMATION_SCHEMA.TABLES WHERE TABLE_NAME='People'
如果没有,在任何表之前创建一个db,或者从屏幕截图判断,只需在代码中添加一个使用测试
$createdb="USE test";
// Execute query
if (mysqli_query($conn,$createdb))
{
echo "Db selected";
}
else
{
echo "Error selecting db: " . mysqli_error($conn);
}
phpmyadmin它说了什么?我使用HeidiSQL
运行查询,表和行显示在我的表中…哦,可能是mysql workbench没有选择默认数据库。在代码中插入一个CREATE DATABASE blah;使用废话;在创建表之前。还是只使用现有的db.use?你什么意思?我以前确实有一个创建数据库脚本,但发现它没有用。是的,请使用数据库名称,以便它知道要使用的数据库。我选择了数据库,但我看不到该表。放弃测试并重新创建它。您对您的用户拥有所有权限吗?您所说的权限是什么意思?我怎么查呢?我还是一无所获。我将phpmyadmin.conf更改为选项索引FollowSymLinks MultiViews AllowOverride all Order Deny,Allow Allow from all