Flash，PHP MySQL…我可以'；似乎无法检索多列数据

我正在同时学习Flash、PHP和MySQL，当然这已经成为一个问题。通过教程和从头开始的代码构建，我已经能够让我定制的Flash应用程序从MySQl数据库中获取一段数据。以下是动作脚本：

gobtn.addEventListener(MouseEvent.CLICK, srchPeople);

function srchPeople(e:MouseEvent):void
{

// Assign a variable name for our URLVariables object
var variables:URLVariables = new URLVariables();

// Build the varSend variable
// Be sure you place the proper location reference to your PHP config file here
var varSend:URLRequest = new URLRequest("http://www.myhost.com/my_php.php");
varSend.method = URLRequestMethod.POST;
varSend.data = variables;

// Build the varLoader variable
var varLoader:URLLoader = new URLLoader;
varLoader.dataFormat = URLLoaderDataFormat.VARIABLES;
varLoader.addEventListener(Event.COMPLETE, completeHandler);

variables.txtBox = txtBox.text;
variables.sendRequest = "parse";

// Send the data to the php file
varLoader.load(varSend);

// When the data comes back from PHP we display it here     
function completeHandler(event:Event):void
{   
    var phpVar1 = event.target.data.var1;
    //var phpVar2 = event.target.data.var2;

    testBox.text = phpVar1;
    testBox.alpha = 87;
    testBox.autoSize ="left";
    modalBox.alpha = 57;

    modalBox.height = testBox.height + 30;
    modalBox.width = testBox.width + 30;
}
}

ActionScript中的所有内容都按照预期的方式执行。我将txtBox的内容发布到PHP，然后从MySQL数据库中获取，然后显示在testBox中……但只有一条信息。我已经用PHP和查询进行了数小时的实验，试图检索该行的多个信息列。我只调用一个变量，如PHP文件中所示：

<?php

mysql_connect("localhost", "mwh", "password"); 
mysql_select_db ("mydb");

// Only run this script if the sendRequest is from our flash application
if ($_POST['sendRequest'] == "parse") 
{
// Access the value of the dynamic text field variable sent from flash
$txtBox = mysql_real_escape_string($_POST['txtBox']);

$query = "SELECT fname FROM People WHERE fname='$txtBox'"; 

$result = mysql_query($query);
//$row = mysql_fetch_array($result)
$first_name = mysql_num_rows($result);

if ($first_name == 0)
    //echo "Name does not exist.";
    print "var1 = $result doesn't exist.";
else
{
        $result = mysql_result($result, 0);
                    /// I've tried using other variables
        print "var1=$result has been retrieved from the database.";

}   


}
mysql_close();
?> 

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1。不要使用mysql函数。他们被弃用了。2.你很容易受到伤害。请勿使用此代码。谢谢。我会尽快修好的。对这个问题有什么建议吗？你会注意注射吗$txtBox=mysql\u real\u escape\u字符串（$\u POST['txtBox']）；更好，但您确实应该使用准备好的语句切换到mysqli或PDO。那你就不用（几乎）担心注射问题了。