PHP：忽略og删除列表末尾的空行

我有一个PHP脚本，它从一个URL获取一个IP地址列表，并在其中添加一些文本和换行符。 这工作得很好，除了源代码末尾有一个空行，这使得一行没有IP地址。 我需要脚本忽略或删除该行，以便不生成该行

<?php
$ipPage = file_get_contents('https://my.pingdom.com/probes/ipv4');
$ipList = explode("\n", $ipPage);
echo "/ip firewall address-list\n";
echo "remove [/ip firewall address-list find list=Pingdom]\n";
foreach($ipList as $ip) {
    echo "add address=" . $ip . " list=Pingdom\n";
  }
?>

您可以在此处看到结果和空的最后一行

<?php
$ipPage = file_get_contents('https://my.pingdom.com/probes/ipv4');
$ipList = preg_split ( "\n", $ipPage , -1 ,PREG_SPLIT_NO_EMPTY );
echo "/ip firewall address-list\n";
echo "remove [/ip firewall address-list find list=Pingdom]\n";
foreach($ipList as $ip) {
    echo "add address=" . $ip . " list=Pingdom\n";
  }
?>

或者这应该管用

<?php
$ipPage = file_get_contents('https://my.pingdom.com/probes/ipv4');
$ipList = explode("\n", $ipPage);
echo "/ip firewall address-list\n";
echo "remove [/ip firewall address-list find list=Pingdom]\n";
foreach($ipList as $ip) {
    if(strlen(trim($ip)) != 0 )
        echo "add address=" . $ip . " list=Pingdom\n";
  }
?>

---

或者，使用

内爆（）

<?php
$ipPage = file_get_contents('https://my.pingdom.com/probes/ipv4');
$ipList = explode("\n", $ipPage);
echo "/ip firewall address-list\n";
echo "remove [/ip firewall address-list find list=Pingdom]\n";
foreach($ipList as $ip) {
    $ips[] = "add address={$ip} list=Pingdom";
}

echo implode("\n", $ips);
?>

谢谢你的回答，我有以下工作要做：

<?php
$ipPage = file_get_contents('https://my.pingdom.com/probes/ipv4');
$ipPage = str_replace("'","",$ipPage);
$ipList = explode("\n", $ipPage);
echo "/ip firewall address-list\n";
echo "remove [/ip firewall address-list find list=Pingdom]\n";
foreach($ipList as $ip) {
    if(strlen($ip) > 0) {
        echo "add address=" . $ip . " list=Pingdom\n";
    }
}
?>

爆炸后是否可以尝试使用
array\u filter
？例如：
$ipList=array\u过滤器（explode（“\n“，$ipPage））
。它将删除每个值等于FALSE的项，并且您只需检查
$ip
var是否真实，比如
foreach（$ipList as$ip）{if（$ip）{echo.…；}
，或者使用trim
$ipPage=trim（$ipPage）。