Php 以特定格式向数组中添加元素
我有一个名为$paises的数组:Php 以特定格式向数组中添加元素,php,arrays,json,Php,Arrays,Json,我有一个名为$paises的数组: Array ( [0] => Array ( [life_sciences] => Array ( [0] => Array ( [value] => Life Sciences
Array
(
[0] => Array
(
[life_sciences] => Array
(
[0] => Array
(
[value] => Life Sciences
)
[1] => Array
(
[value] => 226
)
[2] => Array
(
[value] => 433
)
[3] => Array
(
[value] => 816
)
)
[telecom] => Array
(
[0] => Array
(
[value] => Telecom
)
[1] => Array
(
[value] => 10
)
[2] => Array
(
[value] => 20
)
[3] => Array
(
[value] => 30
)
)
)
)
我需要在另一个json格式的数组中进行转换,如下所示:
{
"dataset": [
{
"seriesname": "Life Sciences",
"data": [{"value": "226"}, {"value": "433"}, {"value": "816"}]
},
{
"seriesname": "Telecom",
"data": [{"value": "10"}, {"value": "20"}, {"value": "30"}]
},
.
.
.
]
}
我正在执行的操作返回错误的数组格式:
$chart = array();
for ($i=0; $i < count($paises); $i++) {
// here i get the value from index 0
$chart["dataset"][]['seriesname'] = $paises[$i]['life_sciences'][0]['value'];
// Here i remove the index 0 and reaorder the array indexes
unset($paises[$i]['life_sciences'][0]);
array_splice($paises[$i]['life_sciences'], 1, 1);
// Here i get all values
$chart["dataset"][]['data'] = $paises[$i]['life_sciences'];
}
请注意,“序列名称”与“数据”分开:
但我需要的是:
{ "seriesname":"Life Sciences" , "data":[{"value":"226"},...] }
如何以正确的方式执行此操作
##########编辑1
我用过:
$chart = array();
for ($i=0; $i < count($paises); $i++) {
$chart["dataset"][$i]['seriesname'] = $paises[$i]['life_sciences'][0]['value'];
$chart["dataset"][$i]['data'] = $paises[$i]['life_sciences'];
$chart["dataset"][$i]['seriesname'] = $paises[$i]['telecom'][0]['value'];
$chart["dataset"][$i]['data'] = $paises[$i]['telecom'];
}
$chart=array();
对于($i=0;$i<计数($paises);$i++){
$chart[“数据集”][$i]['seriesname']=$paises[$i]['life_sciences'][0]['value'];
$chart[“数据集”][$i]['data']=$paises[$i]['life_sciences'];
$chart[“数据集”][$i]['seriesname']=$paises[$i]['telecom'][0]['value'];
$chart[“数据集”][$i]['data']=$paises[$i]['telecom'];
}
但是只返回“telecom”元素,而忽略“life_sciences”请尝试重新格式化数组
<?php
$json = '{
"dataset": [
{
"seriesname": "Life Sciences",
"data": [{"value": "226"}, {"value": "433"}, {"value": "816"}]
}
]
}';
$data = json_decode($json)->dataset;
foreach ($data as $series) {
$tempArr = Array();
foreach ($series->data as $value) {
array_push($tempArr, $value);
}
$series->data = $tempArr;
}
print_r($data);
?>
或speries名称:
$data->seriesname
[]
操作符每次使用时都会创建一个新的数组元素。所以当你这样做的时候:
$chart["dataset"][]['seriesname'] = $paises[$i]['life_sciences'][0]['value'];
$chart["dataset"][]['data'] = $paises[$i]['life_sciences'];
您正在附加新元素,执行此操作时:
$chart["dataset"][]['seriesname'] = $paises[$i]['life_sciences'][0]['value'];
$chart["dataset"][]['data'] = $paises[$i]['life_sciences'];
您正在附加另一个新元素。您可以同时添加它们:
$char["dataset"][] = [
"seriesname" => ...
"data" => ...
];
或者明确指定新索引:
$chart["dataset"][$i]['seriesname'] = ...
$chart["dataset"][$i]['data'] = ...
我认为这对循环体是合适的
编辑1
在你的版本之后,我想应用类似的东西
$k = array_keys($paises[0]); // get array of keys names
for ($i=0; $i < count($k); $i++) { // iterate key names
$chart["dataset"][] = array(
"seriesname" => $paises[0][$k[$i]][0]['value'],
"data" => array_slice($paises[0][$k[$i]], 1) // array without first element
);
}
$k=array_key($paises[0]);//获取密钥名称数组
对于($i=0;$i$paises[0][$k[$i]][0]['value'],
“data”=>array\u slice($paises[0][$k[$i]],1)//不带第一个元素的数组
);
}
使用代码片段形成您的解决方案
如果需要,再添加一个外部循环以迭代$paises
。您可以使用它获取数组的第一个元素(并将其从数组中删除):
谢谢Alex,但对我不起作用,我用新的一期编辑了这个问题
$chart["dataset"][] = array(
"seriesname" => $paises[$i]['life_sciences'][0]['value'],
"data" => array_slice($paises[$i]['life_sciences'], 1)
);
$k = array_keys($paises[0]); // get array of keys names
for ($i=0; $i < count($k); $i++) { // iterate key names
$chart["dataset"][] = array(
"seriesname" => $paises[0][$k[$i]][0]['value'],
"data" => array_slice($paises[0][$k[$i]], 1) // array without first element
);
}
function transformPaisesArray(array $paises): array
{
$transformedPaisesArray = [];
foreach ($paises[0] as $series) {
// Take the first element from the array.
$name = array_shift($series)['value'];
// Add this first element and the rest as a new record to the target array.
$transformedPaisesArray[] = [
'seriesname' => $name,
'data' => $series
];
}
// Wrap everything into the dataset field.
return ['dataset' => $transformedPaisesArray];
}