Php 试图从投票表中计算所有选票，但第153行出现错误

致命错误：无法在第153行的/home/students/gar0349/public_html/project2voting.php中将stdClass类型的对象用作数组

<?php
$totalvotes = ("SELECT COUNT(*) AS total FROM voting WHERE votes >= 0 ");
    $totalvotesresults = mysql_query( $totalvotes )
or die( "Could not get total votes " .mysql_error() );
$data = mysql_fetch_object( $totalvotesresults );
echo "<div>Total number of votes is ". $data['total'] ."</div>\n";;
?>

您正在获取作为对象，因此需要使用作为

$data->total;


echo "<div>Total number of votes is ". $data->total ."</div>\n";;

$data->total；
echo“总票数为”$数据->总计。“\n”；；

$data

是一个对象，而不是数组。
尝试：

echo“总票数为”$数据->总计。“\n”；

从第一行查询中删除第一个括号。。还有

    echo "<div>Total number of votes is ". $data->total ."</div>\n";

echo“总票数为”$数据->总计。“\n”；

我的表格中有8张选票，但在我的输出中显示我总共有5张选票。首先检查您的Where条件。。第二，你可以给我你的表格信息，这样我可以建议..哪一行是153？

echo "<div>Total number of votes is ". $data->total ."</div>\n";

    <?php
$totalvotes = "SELECT COUNT(*) AS total FROM voting WHERE votes >= 0 ";
    $totalvotesresults = mysql_query( $totalvotes )
or die( "Could not get total votes " .mysql_error() );
$data = mysql_fetch_object( $totalvotesresults );
echo "<div>Total number of votes is ". $data->total ."</div>\n";
?>

    echo "<div>Total number of votes is ". $data->total ."</div>\n";