php mysql查询选择匹配精确单词
我想从表中选择匹配的精确单词,但遇到了一个问题 如果row-like:Angel和我确实从表中选择了*,其中row=“Angel”表示成功,并且是第一个 字母很小,大写php mysql查询选择匹配精确单词,php,mysql,Php,Mysql,我想从表中选择匹配的精确单词,但遇到了一个问题 如果row-like:Angel和我确实从表中选择了*,其中row=“Angel”表示成功,并且是第一个 字母很小,大写 $r = mysql_fetch_row(mysql_query("SELECT ID FROM Login WHERE Username = 'angel'
$r = mysql_fetch_row(mysql_query("SELECT ID
FROM Login
WHERE Username = 'angel'
And Password = 'zxc'"));
if($r[0])
die("success");
else
die("failed");
In mysql Table
Username : varchar(50) : Angel
Password varchar(50) : zxc
结果应该是错误的
因为它是天使而不是天使
所以任何解决方案都可以试试这个
$r = mysql_fetch_row(mysql_query("SELECT ID FROM Login WHERE
Password = 'zxc' AND Username collate latin1_general_cs = 'angel'"));
阅读并试着像
SELECT ID
FROM Login
WHERE Username = 'angel' COLLATE utf8_bin;
SELECT ID
FROM Login
WHERE upper(Username) = upper('angel')
您可以使用
BINARY
进行此操作
SELECT * FROM `table` WHERE BINARY `row` = 'angel'
这将使匹配区分大小写。是的,这是由于表字段的排序规则。您应该将其设置为区分大小写的排序规则,通常后缀为
cs
如latin1\u-swedish\u-cs
mysql_query("
ALTER TABLE `Login`
CHANGE `Username` `Username` VARCHAR(250) CHARACTER SET latin1 COLLATE latin1_swedish_ci NOT NULL
");
$r = mysql_fetch_row(mysql_query("SELECT ID FROM Login WHERE Username = 'angel' And Password = 'zxc'"));
if($r[0])
die("success");
else
die("failed");
现在它可以工作了。试试看
SELECT ID
FROM Login
WHERE Username = 'angel' COLLATE utf8_bin;
SELECT ID
FROM Login
WHERE upper(Username) = upper('angel')
您如何知道在何种情况下用户名存储在DB中?它不会总是
ucfirst