Php 我如何比较下面的二维数组？

我只需要基于“value”键的数组1中不存在的元素

阵列1

$array1 = array(
     array('value' => 113214, 'revision_id' => 2047152),
     array('value' => 236462, 'revision_id' => 2045678),
     array('value' => 236541, 'revision_id' => 2047155)
);

阵列2

$array2 = array(
    array('value' => 113214, 'revision_id' => 2047152),
    array('value' => 236461, 'revision_id' => 2047153),
    array('value' => 236541, 'revision_id' => 2047155)
);

我需要如下输出，数组的差异应该基于值

$output = array(
    array('value' => 236462, 'revision_id' => 2045678)
);

---

只需执行嵌套的foreach循环并检查条件，希望它能帮助您：

$arraycheck= array();

foreach($newData as $data1) {

  $duplicatecheck = false;
  foreach($oldData as $data2) {
    if($data1['value'] === $data2['value'] && $data1['revision_id'] === $data2['revision_id']) $duplicatecheck = true;
  }

  if($duplicatecheck === false) $arraycheck[] = $data1;
}

---

只需执行嵌套的foreach循环并检查条件，希望它能帮助您：

$arraycheck= array();

foreach($newData as $data1) {

  $duplicatecheck = false;
  foreach($oldData as $data2) {
    if($data1['value'] === $data2['value'] && $data1['revision_id'] === $data2['revision_id']) $duplicatecheck = true;
  }

  if($duplicatecheck === false) $arraycheck[] = $data1;
}

您可以使用接受最后一个参数的函数作为回调函数，并且可以在这里轻松定义比较

$array1 = [
    ['value' => '113214', 'revision_id' => '2047152'],
    ['value' => '236462', 'revision_id' => '2045678'],
    ['value' => '236541', 'revision_id' => '2047155'],
];
$array2 = [
    ['value' => '113214', 'revision_id' => '2047152'],
    ['value' => '236461', 'revision_id' => '2047153'],
    ['value' => '236541', 'revision_id' => '2047155'],
];

$result = array_udiff ($array1, $array2, function($x, $y) {
    return $x['value'] - $y['value'];
});
print_r($result);

您可以使用接受最后一个参数的函数作为回调函数，并且可以在这里轻松定义比较

$array1 = [
    ['value' => '113214', 'revision_id' => '2047152'],
    ['value' => '236462', 'revision_id' => '2045678'],
    ['value' => '236541', 'revision_id' => '2047155'],
];
$array2 = [
    ['value' => '113214', 'revision_id' => '2047152'],
    ['value' => '236461', 'revision_id' => '2047153'],
    ['value' => '236541', 'revision_id' => '2047155'],
];

$result = array_udiff ($array1, $array2, function($x, $y) {
    return $x['value'] - $y['value'];
});
print_r($result);

摘自：

用法：

$diff = my_array_diff($arr1, $arr2);
var_dump($diff);

摘自：

用法：

$diff = my_array_diff($arr1, $arr2);
var_dump($diff);

首先，使用将“value”的值从array2获取到一维数组中：

$a2values = array_column($array2, 'value');

然后使用这些值排列1

首先，使用将“value”的值从array2获取到一维数组中：

$a2values = array_column($array2, 'value');

然后使用这些值排列1

---

非常感谢..您的代码工作了，但将$duplicate更改为$duplicatecheck，然后工作了。哦，感谢@user3686276的错误谢谢您..您的代码工作了，但将$duplicate更改为$duplicatecheck，然后工作了。哦，感谢@user3686276的错误