如何在现有foreach中为联接的SQL表执行php循环
我目前一直在试图理解如何使用联接表中的SQL结果在现有循环中循环结果 首先,这是我目前的代码:如何在现有foreach中为联接的SQL表执行php循环,php,mysql,arrays,join,foreach,Php,Mysql,Arrays,Join,Foreach,我目前一直在试图理解如何使用联接表中的SQL结果在现有循环中循环结果 首先,这是我目前的代码: <?php include('OrderCore/connect-db.php'); $POIds = array(); if ($result = $mysqli->query("SELECT ProductionOrderID FROM ProductionOrder" ) ) { while ($row = $result->fetch_object()) {
<?php
include('OrderCore/connect-db.php');
$POIds = array();
if ($result = $mysqli->query("SELECT ProductionOrderID FROM ProductionOrder" ) ) {
while ($row = $result->fetch_object()) {
$POIds[] = $row->ProductionOrderID;
}
}
foreach ( $POIds as $index => $OrderId ) {
if ( $result = $mysqli->query("
SELECT *
FROM ProductionOrder AS p
LEFT JOIN ProductionOrderStatus AS s ON ( p.ProductionOrderID = s.ProductionOrderStatusID )
LEFT JOIN NotGood AS n ON ( p.ProductionOrderID = n.NGID )
LEFT JOIN BatchOrder AS b ON ( p.ProductionOrderID = b.ProductionOrderID)
LEFT JOIN Brand AS bd ON ( p.ProductionOrderID = bd.BrandID )
LEFT JOIN CustomerOrder AS co ON ( p.ProductionOrderID = co.COID )
LEFT JOIN Customer AS c ON ( p.ProductionOrderID = c.CustomerID )
LEFT JOIN CustomerOrderStatus AS cos ON ( p.ProductionOrderID = cos.COStatusID )
WHERE p.ProductionOrderID='$OrderId'") ) {
while( $row = $result->fetch_object() ) {
print "<h1>Order: $OrderId</h1>";
print "<table class='table table-striped'>";
print "<tr> <th>PO ID</th> <th>PO #</th> <th>Order Quantity</th> <th>Balance Left</th> <th>Production Date</th> <th>Production Order Status</th> <th>Not Good ID</th> </tr>";
print "<td>" . $row->ProductionOrderID . "</td>";
print "<td>" . $row->PONum . "</td>";
print "<td>" . $row->OrderQTY . "</td>";
print "<td>" . $row->BalLeftNum . "</td>";
print "<td>" . $row->ProductionDate . "</td>";
print "<td>" . $row->ProductionOrderStatusID . "</td>";
print "<td>" . $row->NGID . "</td>";
print "</tr>";
print "</table>";
//BatchOrder
print "<table class='table table-striped'>";
print "<tr> <th>Batch ID</th> <th>Brand Name</th> <th>Batch Quantity</th> <th>Availability Date</th> <th>Remaining Balance</th> <th>Production Order ID</th> </tr>";
print "<td>" . $row->BatchID . "</td>";
print "<td>" . $row->BrandID . "</td>";
print "<td>" . $row->BatchQTY . "</td>";
print "<td>" . $row->AvailDate . "</td>";
print "<td>" . $row->RemainBal . "</td>";
print "<td>" . $row->ProductionOrderID . "</td>";
print "</tr>";
print "</table>";
//CustomerOrder
print "<table class='table table-striped'>";
print "<tr> <th>Customer ID</th> <th>Customer Name</th> <th>Invoice Quantity</th> <th>Invoice #</th> <th>Shipping Date</th> <th>Batch ID</th> <th>CO Status</th> </tr>";
print "<td>" . $row->COID . "</td>";
print "<td>" . $row->CustomerID . "</td>";
print "<td>" . $row->InvoiceQTY . "</td>";
print "<td>" . $row->InvoiceNum . "</td>";
print "<td>" . $row->ShipDate . "</td>";
print "<td>" . $row->BatchID . "</td>";
print "<td>" . $row->COStatusID . "</td>";
print "</tr>";
print "</table>";
}
}
else
{
print "No results to display!";
}
}
$mysqli->close();
?>
您需要将主键连接到相应的外键,例如:
LEFT JOIN ProductionOrderStatus AS s ON ( p.ProductionOrderID = s.ProductionOrderStatusID )
应该是
LEFT JOIN ProductionOrderStatus AS s ON ( p.ProductionOrderID = s.ProductionOrderID )
在大多数联接中都存在相同的问题。为提供示例干杯,我已更正了SELECT语句。然而,现在我只看到了
productionorder
的一次迭代,仍然只看到BatchOrder
和CustomerOrder
的一次迭代
LEFT JOIN ProductionOrderStatus AS s ON ( p.ProductionOrderID = s.ProductionOrderID )