Php 更换从外部div拉出的连杆部分

我有以下代码来提取外部div的内容并显示在我的网页上：

使输出链接中的第一个字母大写的第一个som样式：

<style>
h1:first-letter {text-transform: uppercase;} /* make first letter in link upper-case */
h1 {margin-bottom: -15px; font-size:1.2em;}
p {margin-bottom: 5px;}
a {text-decoration: none;}
</style>

我还编辑了原始代码，以反映我所做的最新更改

---

谢谢

您应该影响

str\u replace

：

$content = str_replace('./opening', 'https://ekstern.vuq.visma.com/ra_recruitment/opening', $content);

使用preg_替换方法：

$url = '<a href="./opening;jsessionid=E2A19018E967B4771224A9FA515AFBC0?0-1.ILinkListener-content-contentPanel-openings~view~container-openings~view-0-details"><span style="font-weight:bold;">fagarbeider</span></a>';

// What do you want to replace ?
$patterns = array(
    '#\./opening;jsessionid=.*\?#',
    '#<a href=#',
    '#span(.*?)>#'
);

// By What ?
$replaces = array(
    'https://ekstern.vuq.visma.com/ra_recruitment/opening?',
    '<a target="_blank" href=',
    'h1>'
);

echo preg_replace($patterns, $replaces, $url);

$url=''；
//你想替换什么？
$patterns=数组(
“#\./开始；JSSessionId=.*\？#”，
“#

我让代码简单而愚蠢。

<?php
$url = 'https://ekstern.vuq.visma.com/ra_recruitment/';
$content = file_get_contents($url);
$content1=str_replace('./opening', 'https://ekstern.vuq.visma.com/ra_recruitment/opening', $content);
$first_step = explode( '<div id="ide">' ,  $content1 );
$second_step = explode("</div>" , $first_step[1] );

echo $second_step[0], $second_step[1], $second_step[2], $second_step[3], $second_step[4], $second_step[5], $second_step[6];
?>  

谢谢，这解决了问题！但随后又出现了一个新问题。似乎从原始页面提取的url包含一个

jsessionid

字符串，我需要删除该字符串才能正常工作。添加了

str replace

后提取的url:

https://ekstern.vuq.visma.com/ra_recruitment/opening；jsessionid=48311227429D90F89603CFA1D3EF3859？0-1.ILinkListener内容面板开口~view~容器开口~view-0-details

我需要它是什么：

https://ekstern.vuq.visma.com/ra_recruitment/opening?0-1.ILinkListener内容面板开口~view~容器开口~view-0-details

有什么有效的方法来解决这个问题吗？你能告诉我吗它显示您的帖子并显示您的原始数据（$content from file\u get\u contents）还有你需要的原始输出？我认为有一种更优雅的方式来达到想要的结果，只需使用preg_replace。谢谢@bang，我在原始帖子中编辑了代码，并添加了原始rata。我想我不会让它像我想要的那样工作，但如果它可以优化，那将是完美的。谢谢，这也很有效，我编辑了o新代码的原始帖子。

$url = '<a href="./opening;jsessionid=E2A19018E967B4771224A9FA515AFBC0?0-1.ILinkListener-content-contentPanel-openings~view~container-openings~view-0-details"><span style="font-weight:bold;">fagarbeider</span></a>';

// What do you want to replace ?
$patterns = array(
    '#\./opening;jsessionid=.*\?#',
    '#<a href=#',
    '#span(.*?)>#'
);

// By What ?
$replaces = array(
    'https://ekstern.vuq.visma.com/ra_recruitment/opening?',
    '<a target="_blank" href=',
    'h1>'
);

echo preg_replace($patterns, $replaces, $url);

<?php
$url = 'https://ekstern.vuq.visma.com/ra_recruitment/';
$content = file_get_contents($url);
$content1=str_replace('./opening', 'https://ekstern.vuq.visma.com/ra_recruitment/opening', $content);
$first_step = explode( '<div id="ide">' ,  $content1 );
$second_step = explode("</div>" , $first_step[1] );

echo $second_step[0], $second_step[1], $second_step[2], $second_step[3], $second_step[4], $second_step[5], $second_step[6];
?>