Php CodeIgniter模型在我的查询中插入额外字符

我正在CodeIgniter模型中执行一个查询以下是我的代码：

if($query = $this->db->select('postID, users.userID, users.userFirstName, users.userLastName, postTitle, postDescription, postHtmlContent, date_format(creationDate, "%d %b, %Y") as creationDate, date_format(updationDate, "%d %b, %Y") as updationDate, cover, postType')->from('posts, users')->where('users.userID = posts.userID and postID = 1 and postStatus = "APPROVED"')->get()){
            return $query->result()[0];
        }else{
            return NULL;
        }

虽然在mysql控制台上执行此查询工作正常，但在CodeIgniter的活动记录模式下，

date\u格式

部分引入了一些额外字符。这是CodeIgniter显示的错误，所有额外字符都以

date\u格式清晰可见（creationDate，

%d

%b，

%Y”）

部分

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'FROM (`posts`, `users`) WHERE `users`.`userID` = posts.userID and postID = 1 and' at line 2

SELECT `postID`, `users`.`userID`, `users`.`userFirstName`, `users`.`userLastName`, `postTitle`, `postDescription`, `postHtmlContent`, date_format(creationDate, `"%d` %b, `%Y")` as creationDate, date_format(updationDate, `"%d` %b, `%Y")` as updationDate, `cover`, `postType` FROM (`posts`, `users`) WHERE `users`.`userID` = posts.userID and postID = 1 and postStatus = "APPROVED"

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我该如何处理这个问题？如有任何帮助，将不胜感激。感谢您删除反勾号，您必须向所选零件添加第二个可选参数（FALSE）：

$this->db->select("postID, userID, . . .", FALSE);

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只需添加

false

作为select的第二个参数，这样codeigniter就不会转换格式

if($query = $this->db->select('postID, users.userID, users.userFirstName, users.userLastName, postTitle, postDescription, postHtmlContent, date_format(creationDate, "%d %b, %Y") as creationDate, date_format(updationDate, "%d %b, %Y") as updationDate, cover, postType',false)->from('posts, users')->where('users.userID = posts.userID and postID = 1 and postStatus = "APPROVED"')->get()){
        return $query->result()[0];
    }else{
        return NULL;
    }

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谢谢，我在某处看到过，但没有找到任何关于为什么要添加此项的参考。