使用PHP调用公共Instagram JSON数据并将其分配给变量

目标：

$post1_likes = number of likes from post;
$post1_comments = number of comments from post;

$post2_likes = number of likes from post;
$post2_comments = number of comments from post;

$post3_likes = number of likes from post;
$post3_comments = number of comments from post;

$combine_all = $post1_likes + $post1_comments + $post2_likes + $post2_comments $post3_likes + $post3_comments;

return combine_all;

我的目标是获得Instagram帐户最后3篇帖子的喜欢和评论的总数，并将它们分配给不同的变量

问题：

$post1_likes = number of likes from post;
$post1_comments = number of comments from post;

$post2_likes = number of likes from post;
$post2_comments = number of comments from post;

$post3_likes = number of likes from post;
$post3_comments = number of comments from post;

$combine_all = $post1_likes + $post1_comments + $post2_likes + $post2_comments $post3_likes + $post3_comments;

return combine_all;

我可以调用的总喜欢和评论的最新职位，我不知道如何调用其他职位的信息。我已经试了好几个小时了

目标的逻辑解释：

$post1_likes = number of likes from post;
$post1_comments = number of comments from post;

$post2_likes = number of likes from post;
$post2_comments = number of comments from post;

$post3_likes = number of likes from post;
$post3_comments = number of comments from post;

$combine_all = $post1_likes + $post1_comments + $post2_likes + $post2_comments $post3_likes + $post3_comments;

return combine_all;

当前代码：

$post1_likes = number of likes from post;
$post1_comments = number of comments from post;

$post2_likes = number of likes from post;
$post2_comments = number of comments from post;

$post3_likes = number of likes from post;
$post3_comments = number of comments from post;

$combine_all = $post1_likes + $post1_comments + $post2_likes + $post2_comments $post3_likes + $post3_comments;

return combine_all;

$raw=file\u get\u contents（'https://www.instagram.com/instagram');
preg\u match（“/\”edge\u media\u preview\u like\”\：\s？{“count\”\：\s？（[0-9]+）/”，$raw，$m1）；
preg\u match（'/\'edge\u media\u to\u comment\\：\s？\{\'count\'\：\s？（[0-9]+）/'，$raw，$m2）；
$combine_all=$m2[1]+$m1[1]；
返回$combine\u all；

数据链接：

$post1_likes = number of likes from post;
$post1_comments = number of comments from post;

$post2_likes = number of likes from post;
$post2_comments = number of comments from post;

$post3_likes = number of likes from post;
$post3_comments = number of comments from post;

$combine_all = $post1_likes + $post1_comments + $post2_likes + $post2_comments $post3_likes + $post3_comments;

return combine_all;

我是PHP新手，非常感谢您的帮助！

---

感谢您

在阅读JSON之前，您已经阅读了好几层数据，然后才开始阅读后面的信息。下面的代码应该让您开始了解需要做什么

// Decode the data to a nested associative array
$json = json_decode($raw, true);

// Loop through each of the edges
foreach ( $json['graphql']['user']['edge_felix_video_timeline']['edges'] as $edge ){
    echo $edge['node']['edge_media_to_comment']['count'].'/'
        .$edge['node']['edge_media_preview_like']['count'].PHP_EOL;
}

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第二个答案是使用CURL进行时间优化，这将只添加前三个值

$website_url = 'https://www.instagram.com/instagram/?__a=1';
$curl = curl_init();
curl_setopt($curl, CURLOPT_SSL_VERIFYPEER, FALSE);
curl_setopt($curl, CURLOPT_HEADER, false);
curl_setopt($curl, CURLOPT_FOLLOWLOCATION, true);
curl_setopt($curl, CURLOPT_URL, $website_url);
curl_setopt($curl, CURLOPT_REFERER, $website_url);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, TRUE);
curl_setopt($curl, CURLOPT_USERAGENT, 'Mozilla/5.0(Windows NT 6.1; rv:8.0) Gecko/20100101 Firefox/66.0');
$str = curl_exec($curl);
curl_close($curl);
$json = json_decode($str, true);

$combine_all=0; $loop = 0; 
foreach($json['graphql']['user']['edge_felix_video_timeline'] ['edges'] as $key=>$node){
        if(($node['node']['edge_media_to_comment']['count']>0 || $node['node']['edge_media_preview_like']['count']>0) && ($loop<4)){ // if you need add first only three then $loop<4
            $combine_all += $node['node']['edge_media_preview_like']['count'] + $node['node']['edge_media_to_comment']['count'];
            $loop++;
        }
}
echo "combine_all : ";
print_r($combine_all);

---

$raw

是否包含JSON？如果是的话，$raw包含我附加的链接中的JSON数据。我已经遇到过这个问题，但我发现很难理解：（这似乎包括数组中的所有帖子，而不是最后3篇（这很好）。我已经实现了这段代码，但是它似乎会大大降低页面速度，你知道为什么吗？它甚至会导致网关超时。。是的，因为你从应用程序/网站上抓取数据会占用大量数据。当然，获取特定数据需要时间。我们可以使用它进行检查，这样可以缩短时间。@cactusboat现在使用curl it gi检查我的第二个答案我的结果很快就和上一个相比了。如果很好，别忘了把这个标记为回答谢谢@Rasa Mohamed！我已经用我自己的代码实现了curl部分，它使我的网站从GTMetrix上的16秒降到了2秒！难以置信，谢谢！