处理';新';PHP单元测试中的关键字

处理';新';PHP单元测试中的关键字,php,laravel,unit-testing,doctrine,phpunit,Php,Laravel,Unit Testing,Doctrine,Phpunit,就我而言,我有一门课,比如: class Logger { /** * @var EntityManager */ protected $entityManager; public function __construct(EntityManager $entityManager) { $this->entityManager = $entityManager; } /** * @param Model $model */ public function log(Mod

就我而言,我有一门课,比如:

class Logger
{
/**
 * @var EntityManager
 */
protected $entityManager;

public function __construct(EntityManager $entityManager)
{
    $this->entityManager = $entityManager;
}

/**
 * @param Model $model
 */
public function log(Model $model)
{
    $logEntity = new LogEntity();
    $logEntity->setOrder($model->getOrder());
    $logEntity->setType($model->getType());
    $logEntity->setScore($model->getScore());
    $logEntity->setCreated(new DateTime());
    $logEntity->setModified(new DateTime());

    $this->entityManager->persist($logEntity);
    $this->entityManager->flush();

    return $logEntity;

}
Logger类不可测试,因为在我的代码中存在“new”关键字,另一方面Logger类和EntityManager类在容器中注册了singleton,无法将模型作为依赖项注入。 如何更改类以更改为可测试类?
LoggerModel是一个条令实体,在Laravel框架中使用。

我用一个示例解决了这个问题:工厂模式

我需要断言,所以当从工厂获得新模型时,将其断言为mock

怎么做

我创建了一个类,其方法可以是单例服务:

class LogFactory
{
    public function makeLogEntity()
    {
        return new LogEntity();
    }
}
在另一个服务中,注入工厂类:

class Logger
{
/**
 * @var EntityManager
 */
protected $entityManager;

/**
 * @var LogFactory
 */
protected $logFactory;

public function __construct(EntityManager $entityManager, LogFactory $logFactory)
{
    $this->entityManager = $entityManager;
    $this->logFactory = $logFactory
}

/**
 * @param Model $model
 */
public function log(Model $model)
{
    $logEntity = $this->logFactory->makeLogEntity();
    $logEntity->setOrder($model->getOrder());
    $logEntity->setType($model->getType());
    $logEntity->setScore($model->getScore());
    $logEntity->setCreated(new DateTime());
    $logEntity->setModified(new DateTime());

    $this->entityManager->persist($logEntity);
    $this->entityManager->flush();

    return $logEntity;

}
现在我有了一个可模拟的服务,并在测试中调用
$mock->willReturn()
函数