Cakephp链接警报

我有以下链接指向cake中的删除函数：

    <?php echo $this->Form->postLink(__(''), array('action' => 'delete', $website['Website']['website_id']), array('class' => 'icon-trash   '), null, __('Are you sure you want to delete # %s?', $website['Website']['website_id'])); ?>

现在，正如您所看到的，应该有一条消息说：您确定要删除吗

但当我点击链接时，什么也没发生，当然，我的字段被删除了

那么，如何使链接显示为确认框？

这将起作用

<?php echo $this->Form->postLink(__('Delete'), array(
    'action' => 'delete', $website['Website']['website_id']), array(
    'class' => 'icon-trash'
   ), __('Are you sure you want to delete # %s?', $website['Website']['website_id'])); ?>

这会奏效的

<?php echo $this->Form->postLink(__('Delete'), array(
    'action' => 'delete', $website['Website']['website_id']), array(
    'class' => 'icon-trash'
   ), __('Are you sure you want to delete # %s?', $website['Website']['website_id'])); ?>

---

您需要在下面的结构中添加代码

echo $this->Html->link(
    'Delete',
    array('action' => 'delete', $website['Website']['website_id']),
    array(),
    "Are you sure you wish to delete this recipe?"
);

---

您需要在下面的结构中添加代码

echo $this->Html->link(
    'Delete',
    array('action' => 'delete', $website['Website']['website_id']),
    array(),
    "Are you sure you wish to delete this recipe?"
);

---

因此，您现在要传递五个参数

删除空值，它应该可以工作

echo $this->Form->postLink(
    // title
    __('delete'),
    // URL
    array('controller' => 'documents', 'action' => 'delete', $document['id']),
// Options
array('escape' => false),

// confirmMessage
__('Are you sure you want to delete # %s?', $document['file'])

)； 见文件

---

希望这肯定会对您有所帮助。

因此，您现在要传递五个参数

删除空值，它应该可以工作

echo $this->Form->postLink(
    // title
    __('delete'),
    // URL
    array('controller' => 'documents', 'action' => 'delete', $document['id']),
// Options
array('escape' => false),

// confirmMessage
__('Are you sure you want to delete # %s?', $document['file'])

)； 见文件

希望这一定会对你有所帮助