Php SQL Insert语句挂起

这是我的密码。我没有收到错误语句，但数据没有插入到表中。我尝试在PHPMyAdmin中运行查询，结果很好。这也不是因为用户权限

  if ($mysql->connect_errno) {
        echo("Connect failed: ". $mysql->connect_error);
        die();
    }
    echo "I am confused by this thing<br>";

    if(isset($_POST['upload']) && $_FILES['userfile']['size'] > 0)
    {
        echo "Trying to figure out the errors!!!!<br>";
        $fileName = $mysql->real_escape_string($_FILES['userfile']['name']);
        $tmpName  = $mysql->real_escape_string($_FILES['userfile']['tmp_name']);
        $fileSize = intval($_FILES['userfile']['size']);
        $fileType = $mysql->real_escape_string($_FILES['userfile']['type']);
        echo $fileName."<br>";
        echo $tmpName."<br>";
        echo $fileSize."<br>";
        echo $fileType."<br>";
        //reads the file information
        $fp      = fopen($tmpName, 'r');
        $content = fread($fp, filesize($tmpName));
        $content = $mysql->real_escape_string(addslashes($content));
        fclose($fp);
        //this just adds slashes

这是代码出错的地方。。。它只是挂起，从不打印死亡信息

        $updateDB = $mysqli->query($query) or die($mysqli->error);

它从未打印出这行

        echo "<br>File $fileName uploaded<br>";
    } 

echo“
上传的文件$fileName
”；
} 

您正在使用顶部的

$mysql

对象，突然，您触发了对

$mysqli

对象的查询

改变

$updateDB = $mysqli->query($query) or die($mysqli->error);

到

---

不要将文件内容存储在数据库中（除非有很好的理由）是否有理由在失败的行中从

$mysql

切换到

$mysqli

？

$updateDB = $mysqli->query($query) or die($mysqli->error);

$updateDB = $mysql->query($query) or die($mysql->error);