PHP：如何将PHP数组转换为json格式

我有一组来自mysql查询的数据，如下所示

hub       | month | frequency 
GALAXY    | 10    | 1
GALAXY    | 11    | 2 
GALAXY    | 12    | 1 
LEVERAGES | 10    | 3 
LEVERAGES | 12    | 2 

我想使用json_encode将数据填充为json格式，如下所示：

[{"name":"GALAXY","total":"4","articles":[["10","1"],["11","2"],["12","1"]]},{"name":"LEVERAGES","total":"5","articles":[["10","3"],["12","2"]]}]

但我无法获得正确的json。下面是我的代码：

$root = array();
$aColumns = array('hub', 'month', 'frequency');
$tangos = $this->Report_Model->getMonthHubTango();


    foreach($tangos->result_array() as $aRow)
                    {
                        $row = array();
                        $total = 0;

                        foreach($aColumns as $col)
                        {
                            $row[] = $aRow[$col];
                            $total += $aRow['frequency'];
                                                    $hub = $aRow['hub'];

                        }
                        $main['name'] = $hub;
                        $main['total'] = $total;
                        $main['articles'][] = $row;                 

                    }

                    $root[] = $main;
echo json_encode($root);

---

有人吗？提前感谢。

我认为，您应该添加

$root[]=$main编码到foreach块中，因此每个$main数组都将放入$root矩阵中：

foreach($tangos->result_array() as $aRow)

{
    $row = array();
    $total = 0;

    foreach($aColumns as $col)
    {
        $row[] = $aRow[$col];
        $total += $aRow['frequency'];

    }
    $main['name'] = $hub;
    $main['total'] = $total;
    $main['articles'][] = $row;                 
    $root[] = $main;
}

另外，循环中还有$hub未定义。因此，$main['name']可能是未定义的。
如上所述，但是如果您想给根目录一个属性，这将允许您保持数据的组织。使用
$root['data']=$main。因此，该守则将成为：

$root = array();
$tangos = $this->Report_Model->getMonthHubTango();


    foreach($tangos->result_array() as $aRow)
                    {
                        $row = array();
                        $total = 0;

                        foreach($aColumns as $col)
                        {
                            $row[] = $aRow[$col];
                            $total += $aRow['frequency'];

                        }
                        $main['name'] = $hub;
                        $main['total'] = $total;
                        $main['articles'][] = $row;                 
                        $root[] = $main;
                    }


echo json_encode($root);

foreach($tangos->result_array() as $aRow){
    $row = array();
    $total = 0;

    foreach($aColumns as $col) {
        $row[] = $aRow[$col];
        $total += $aRow['frequency'];
        $hub = $aRow['hub'];

    }
    $main['name'] = $hub;
    $main['total'] = $total;
    $main['articles'][] = $row;                 
}

$root['data'] = $main;
echo json_encode($root);

您的代码中定义了
$hub
在哪里？它看起来像
$main['name']
和其他两个
$main
在每次
迭代中都会被覆盖，所以您只能得到
$root[]
或
$root['name']
的最后一次迭代结果。@Nikolay是的，完全去掉$root