Php 如何按类别id包含两个文件
我有一个文件要放在这个文件中,另外两个文件是动态的。主文件如下所示:Php 如何按类别id包含两个文件,php,mysql,if-statement,include,Php,Mysql,If Statement,Include,我有一个文件要放在这个文件中,另外两个文件是动态的。主文件如下所示: <!doctype html> <html> <head> <meta charset="utf-8"> <title>Gaming Ventus Let's Play - VLet's Play</title> <link rel="shortcut icon" href="images/favicon.ico"> <link rel=
<!doctype html>
<html>
<head>
<meta charset="utf-8">
<title>Gaming Ventus Let's Play - VLet's Play</title>
<link rel="shortcut icon" href="images/favicon.ico">
<link rel="stylesheet" type="text/css" href="../styles/article_style_readmore.css">
<link rel="stylesheet" type="text/css" href="../../styles/styles_content_static_contact/styles_alltemplate_static_contact.css">
<link rel="stylesheet" type="text/css" href="../styles/readmore_mainbody_style.css">
<link rel="stylesheet" type="text/css" href="../../test/test2/Untitled-3.css">
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<body>
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/****************************************************************\
<?php
include('function_art_result_readmore.php');
include('function_art_result_readmore_photos.php');
?>
\****************************************************************/
</div>
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<div id="right_nav_about">
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<div class="right_nav_others">
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<p>Copyright Ventus Gaming</p>
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<?php
//Ayto einai to apotelesma otan patas to read more dhladh ta post mona tous
?>
</body>
</html>
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所以在星号部分我有两个文件,我想包括。。。这些文件有mysql代码和php代码。所以我想把它们包括进来,像这样:
<?php
if ($CatID == 8) {
include('function_art_result_readmore.php');
} else {
include('function_art_result_readmore_photos.php');
}
?>
但这是行不通的,只是举个例子。所以我想按类别id打开include文件,这样我就可以随时拥有这两个文件。
当然,如果有其他解决方案,我会接受:)
提前谢谢你 在请求中传递类别ID(使用以下代码获取或发布):
`您从何处获得当前类别ID?我有一个数据库,其中有“类别ID”列。如果是您要求的。不工作:/它会在所有类别中打开此文件:function\u art\u result\u readmore\u photos.php。您能粘贴请求url吗?您的意思是?在请求参数GET/POST.中传递类别id。。(我在这个示例链接中作为GET-request-param传递)很抱歉,我不在pc中。所以我现在尝试一下,它工作得非常好。。。谢谢!如果需要,只需编辑以上答案即可完成:)
if(isset($_REQUEST['category_id']) && $_REQUEST['category_id'] == '8') {
include('function_art_result_readmore.php');
} else {
include('function_art_result_readmore_photos.php');
}