在PHP MySQL上显示、连接、计数和分组6个表

在PHP MySQL上显示、连接、计数和分组6个表,php,mysql,join,count,group-by,Php,Mysql,Join,Count,Group By,我在用php和mysql显示、连接和分组6个表时遇到问题 我的桌子 loker_工作:id_工作、slug_工作、职位、部门、级别、位置 loker_部门:id_部门,名称_部门 loker_级别:id_级别、名称_级别 loker_位置:id_位置、名称_位置 loker_申请人:身份证、工作、文件 loker_用户:id_用户,名称 我的查询 SELECT loker_job.slug_job, loker_level.name_level, loker_location.name_l

我在用php和mysql显示、连接和分组6个表时遇到问题

我的桌子

  • loker_工作:id_工作、slug_工作、职位、部门、级别、位置

  • loker_部门:id_部门,名称_部门

  • loker_级别:id_级别、名称_级别

  • loker_位置:id_位置、名称_位置

  • loker_申请人:身份证、工作、文件

  • loker_用户:id_用户,名称

我的查询

SELECT 
loker_job.slug_job,
loker_level.name_level,
loker_location.name_location,
loker_department.name_department,
loker_user.name,
loker_applicant.file,
count(*) as total_applicant
FROM
loker_job
LEFT JOIN loker_department ON loker_department.id_department =    loker_job.department
LEFT JOIN loker_level ON loker_level.id_level = loker_job.`level`
LEFT JOIN loker_location ON loker_location.id_location = loker_job.location
LEFT JOIN loker_user ON loker_user.id_user = loker_job.publisher
LEFT JOIN loker_applicant ON loker_applicant.id_job = loker_job.slug_job
GROUP by loker_job.slug_job
我想要这样的结果:

+----------+-----------------+-----------------+---------------+----------------------+-----------------+
| slug_job | name_level      | name_department | name_location | name_position        | total applicant |
+----------+-----------------+-----------------+---------------+----------------------+-----------------+
| 1111     | General Manager | Marketing       | America       | Vice General Manager | 3               |
| 2222     | E-officer       | Ecommerce       | Japan         | Officer              | 1               |
| 3333     | General Manager | Sales           | Rusia         | Vice General Manager | 0               |
| 4444     | General Manager | Marketing       | America       | Vice General Manager | 3               |
+----------+-----------------+-----------------+---------------+----------------------+-----------------+
结果

但是,我得到的结果是:

  • 有一行或多行始终结果为1总申请者,尽管从db显示0或无
  • 总计行不正确,总计数据中始终为-1
任何帮助都将不胜感激,感谢您首先使用“loker_user”表,并使用关系表进行外部联接。根据以下描述:

SELECT loker_job.slug_job, loker_level.name_level, loker_location.name_location,
loker_department.name_department, A.name, loker_applicant.file, IFNULL(A.total_applicant,0) as total_applicant
FROM loker_job
LEFT OUTER JOIN loker_department ON loker_department.id_department =   loker_job.department
LEFT OUTER JOIN loker_level ON loker_level.id_level = loker_job.`level`
LEFT OUTER JOIN loker_location ON loker_location.id_location = loker_job.location
LEFT OUTER JOIN loker_applicant ON loker_applicant.id_job = loker_job.slug_job
LEFT OUTER JOIN (
select id_user,name, count(*) as total_applicant from loker_user group by id_user, name
) as A ON A.id_user = loker_job.publisher

它在“on子句”中将列名从“a.loker_job”更新为“loker_job.loker_job”中显示未知列“a.publisher”。