Php 未定义的属性：数组到对象的转换

我有这个数组，我打算将其转换为一个对象，以便在我的laravel刀片中使用，但访问属性会不断抛出错误

$applicationDetail=（对象）数组([
“completedApplication”=>3，
“不完整应用程序”=>4，
“totalApplication”=>5，
]);
dd（$applicationDetail->completedApplication）我不知道数组中的格式。看来方括号是没有必要的。尝试：

$applicationDetail = (object) array(
        'completedApplication' => 3,
        'incompleteApplication' => 4,
        'totalApplication' => 5,
    );
dd($applicationDetail->completedApplication);

我不知道你的数组是什么格式。看来方括号是没有必要的。尝试：

$applicationDetail = (object) array(
        'completedApplication' => 3,
        'incompleteApplication' => 4,
        'totalApplication' => 5,
    );
dd($applicationDetail->completedApplication);

喜欢吗

  $applicationDetail = (object) [
      'completedApplication' => 3,
      'incompleteApplication' => 4,
      'totalApplication' => 5,
  ];

dd($applicationDetail->completedApplication); // will give output 3

如果要创建二维数组，则要创建二维数组

$applicationDetail = (object) array([
      'completedApplication' => 3,
      'incompleteApplication' => 4,
      'totalApplication' => 5,
  ]);
print_r($applicationDetail);

它将显示输出

stdClass Object
(
    [0] => Array
        (
            [completedApplication] => 3
            [incompleteApplication] => 4
            [totalApplication] => 5
        )

)

喜欢吗

  $applicationDetail = (object) [
      'completedApplication' => 3,
      'incompleteApplication' => 4,
      'totalApplication' => 5,
  ];

dd($applicationDetail->completedApplication); // will give output 3

如果要创建二维数组，则要创建二维数组

$applicationDetail = (object) array([
      'completedApplication' => 3,
      'incompleteApplication' => 4,
      'totalApplication' => 5,
  ]);
print_r($applicationDetail);

它将显示输出

stdClass Object
(
    [0] => Array
        (
            [completedApplication] => 3
            [incompleteApplication] => 4
            [totalApplication] => 5
        )

)