Php 如何在使用'；进入输出文件'；查询

我使用此查询创建mysql DB表的CSV

  $path = getcwd() . '/uploads/data.csv' ;

   $sql = "select email,username from `engine4_user` LIMIT 5000 into outfile '$path' FIELDS TERMINATED BY ','  LINES TERMINATED BY '\n' ";

但是现在我需要一个额外的字段，那就是profileurl，它在表中不存在。因此，我想使用该用户表的ID创建一个虚拟url列。比如$user\u id

请帮忙。提前感谢。

使用“CONCAT”操作符

$sql = "SELECT
        email,
        username, 
        CONCAT('https://mysiteurl/profile/',user_id) as profile_url 
        FROM `engine4_user` 
        LIMIT 5000 
        into outfile '$path' FIELDS TERMINATED BY ','  LINES TERMINATED BY '\n' ";