Warning: file_get_contents(/data/phpspider/zhask/data//catemap/1/php/291.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181

Warning: file_get_contents(/data/phpspider/zhask/data//catemap/1/wordpress/11.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181
如何在php中获取对象的属性值?_Php_Wordpress - Fatal编程技术网

如何在php中获取对象的属性值?

如何在php中获取对象的属性值?,php,wordpress,Php,Wordpress,我在wordpress中有一个自定义的帖子类型,我想获取它的类别,这样我就可以将它们列为过滤器选项。我曾经 $terms = get_terms(array( 'post_type' => 'leadership', 'hide_empty'=> false, )); 但我很难弄清楚如何从中得到任何东西 对象的块是: Array ( [0] => WP_Term Object ( [term_id] => 3 [name] => Finance 我要你的名字

我在wordpress中有一个自定义的帖子类型,我想获取它的类别,这样我就可以将它们列为过滤器选项。我曾经

$terms = get_terms(array(
'post_type' => 'leadership',
'hide_empty'=> false,
));
但我很难弄清楚如何从中得到任何东西

对象的块是:

Array ( [0] => WP_Term Object ( [term_id] => 3 [name] => Finance 
我要你的名字

I wrote $names = $terms->name;
但这似乎并不奏效

这在php中是如何处理的?

使用下面的代码

$terms = get_terms(array(
'post_type' => 'leadership',
'hide_empty'=> false,
));
 // loop the results
foreach ( $terms as $term ) {
    echo $term->name ;
}

尝试以下代码获取所有类别
$names=array_column($terms,'name')

您可以
var\u dump($terms),它将显示其中包含的内容。请尝试使用
$names=$terms[0]->name