PHP/MySql-DateTime检测是否分配了值?
我想做一个if语句,它只在datetime值不为null时运行PHP/MySql-DateTime检测是否分配了值?,php,mysql,datetime,Php,Mysql,Datetime,我想做一个if语句,它只在datetime值不为null时运行(0000-00-00 00:00:00) 我已通过查询将值传递到变量中,但如何确定它是否等于0000-00-00 00:00:00 $query = "SELECT * FROM stats WHERE member_id='" . $_SESSION['SESS_MEMBER_ID'] . "' "; $result = mysql_query($query); while($row = mysql_fetch_array($
(0000-00-00 00:00:00)
我已通过查询将值传递到变量中,但如何确定它是否等于0000-00-00 00:00:00
$query = "SELECT * FROM stats WHERE member_id='" . $_SESSION['SESS_MEMBER_ID'] . "' ";
$result = mysql_query($query);
while($row = mysql_fetch_array($result, MYSQL_ASSOC))
{
$money = $row['money'];
$bank_money = $row['bank_money'];
$ap = $row['ap'];
$exp = $row['exp'];
$last_ap_update = $row['last_ap_update'];
}
if ($last_ap_update != ){ //Can i verify its NULL-ness here so i can run this if stament or run else?
}
$last\u ap\u update!=STROTIME(“0000-00-00 00:00:00”)
为什么不直接比较它:
if ($last_ap_update != "0000-00-00 00:00:00")
{
//do whatever.
}
将其存储到变量中,以便将其用作字符串
if ($last_ap_update != "0000-00-00 00:00:00"){
}
为什么不将比较添加到sql语句中
$query = "SELECT * FROM stats WHERE member_id='" . $_SESSION['SESS_MEMBER_ID'] . "' AND last_ap_update > 0";
是的,你可以使用
>0
,但是如果你愿意,你也可以使用'0000-00-00 00:00:00'
。哦,我不知道。我认为datetime值不能与字符串进行比较。datetime值只是格式化的字符串吗?看起来您最多只能获取一行。你不需要一个while循环。
$query = "SELECT * FROM stats WHERE member_id='" . $_SESSION['SESS_MEMBER_ID'] . "' AND last_ap_update > 0";