Php 无法使用Guzzle 6.x从Twilio获取api数据

我正在试图检索我发送的传真列表。根据Twilio的文档，我可以在获取列表（当然我必须提供我的authtoken和sid）。我现在正试图用Guzzle 6.x复制同样的东西。这是我的代码（我使用的是codeigniter 3.x）：

运行代码后，我在$this->data['status\u code']、$this->data['content\u type']和$this->data['faxes']的视图文件中看到以下内容：

$this->data['status\u code']显示200 $this->data['content\u type']表示应用程序/json $this->data['faxes']没有提供我可以在上看到的传真列表。相反，它显示：

GuzzleHttp\Psr7\Stream Object (
 [stream:GuzzleHttp\Psr7\Stream:private] => Resource id #47
 [size:GuzzleHttp\Psr7\Stream:private] => 
 [seekable:GuzzleHttp\Psr7\Stream:private] => 1
 [readable:GuzzleHttp\Psr7\Stream:private] => 1
 [writable:GuzzleHttp\Psr7\Stream:private] => 1
 [uri:GuzzleHttp\Psr7\Stream:private] => php://temp
 [customMetadata:GuzzleHttp\Psr7\Stream:private] => Array
    (
    )

)

我如何获得传真信息，传真信息应如下所示：

"meta": {"page": 0, "page_size": 50, "first_page_url": 
"https://fax.twilio.com/v1/Faxes?PageSize=50&Page=0", "previous_page_url": 
null, "url": "https://fax.twilio.com/v1/Faxes?PageSize=50&Page=0", 
"next_page_url": null, "key": "faxes"}, "faxes": [{"media_sid": 
"*snip*", "status": "delivered", "direction": "outbound", "from": 
"+81removed", "date_updated": "2019-01-02T08:16:43Z", "price": "-21.6", 
"account_sid": "*snip*", "to": "+81removed", "date_created": "2019-01- 
02T08:13:15Z", "url": 
"https://fax.twilio.com/v1/Faxes/FXe588329bf71f3f411da742d84838a25a", "sid": 
"*snip*", "duration": 193, "num_pages": 1, "quality": "fine", "price_unit": 
"JPY", "api_version": "v1", "media_url": 
"https://media.twiliocdn.com/fax/*snip*/*snip?x-amz-security-   etc etc

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非常感谢您的指导。

Guzzle 6执行psr7。要访问内容，正确的方法是：

$this->data['faxes'] = $res->getBody()->getContents();

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服务器上是否安装了cURL？我没有使用cURL

$this->data['faxes'] = $res->getBody()->getContents();