当用户登录PHP时显示其名称_Php

当用户登录PHP时显示其名称

php

当用户登录PHP时显示其名称,php,Php,正如我在标题中所说，我想当用户登录网站时，在一些地方显示他/她的名字。因此，我有一个如下的欢迎页面： <body> <div id='fg_membersite_content'> <h2>Home Page</h2> Welcome back <?= $fgmembersite->UserFullName(); ?>! </body> 还有另外一个功能： function CheckLoginInDB($user

正如我在标题中所说，我想当用户登录网站时，在一些地方显示他/她的名字。因此，我有一个如下的欢迎页面：

<body>
<div id='fg_membersite_content'>
<h2>Home Page</h2>
Welcome back <?= $fgmembersite->UserFullName(); ?>! 
</body>

还有另外一个功能：

function CheckLoginInDB($username,$password)
{
    if(!$this->DBLogin())
    {
        $this->HandleError("Database login failed!");
        return false;
    }          
    $username = $this->SanitizeForSQL($username);
    $pwdmd5 = md5($password);
    $qry = "Select name, email from $this->tablename where username='$username' and password='$pwdmd5' and confirmcode='y'";
    $result =mysql_query("SET CHARACTER SET  utf8");
    $result = mysql_query($qry,$this->connection);

    if(!$result || mysql_num_rows($result) <= 0)
    {
        $this->HandleError("Error logging in. The username or password does not match");
        return false;
    }

    $row = mysql_fetch_assoc($result);


    $_SESSION['name_of_user']  = $row['name'];
    $_SESSION['email_of_user'] = $row['email'];

    return true;
}

正在使用符号，其中在哪里创建类对象？如果它不是一个类，那么什么是
$fgmembersite
？你的页面名有.php扩展名还是.html扩展名？如果你查看源代码，我想你会发现你有
，那么
是否启用了php短标记？是否有可能重复 function CheckLoginInDB($username,$password) { if(!$this->DBLogin()) { $this->HandleError("Database login failed!"); return false; } $username = $this->SanitizeForSQL($username); $pwdmd5 = md5($password); $qry = "Select name, email from $this->tablename where username='$username' and password='$pwdmd5' and confirmcode='y'"; $result =mysql_query("SET CHARACTER SET utf8"); $result = mysql_query($qry,$this->connection); if(!$result || mysql_num_rows($result) <= 0) { $this->HandleError("Error logging in. The username or password does not match"); return false; } $row = mysql_fetch_assoc($result); $_SESSION['name_of_user'] = $row['name']; $_SESSION['email_of_user'] = $row['email']; return true; } Welcome back UserFullName(); ?>! <?= $fgmembersite->UserFullName(); ?>