Php mysqli_fetch_assoc（）正在提供意外的空值

这是我的SQL查询：

SELECT * FROM users,content 
LEFT OUTER JOIN articles ON ( 
  content.content_id = articles.content_id 
  AND content.content_type = 'article' ) 
LEFT OUTER JOIN projects ON ( 
  content.content_id = projects.content_id 
  AND content.content_type = 'project' )
LEFT OUTER JOIN videos ON ( 
  content.content_id = articles.content_id
  AND content.content_type = 'video' ) 
WHERE (content.content_id IN (128,414,399,616,259)) 
AND content.author_id = users.u_id 
order by FIELD(content.content_id,128,414,399,616,259)

当我在phpmyadmin上运行此操作时，我得到的结果是正确的，但当我通过mysqli\u fetch\u assoc（）获取结果时，我得到的内容\u id值为空。请有人帮我解决这个问题。提前谢谢

编辑： 这是我的php代码

$query = "SELECT * 
      FROM   users,content
        LEFT OUTER JOIN articles 
                    ON ( content.content_id = articles.content_id 
                         AND content.content_type = 'article' ) 
        LEFT OUTER JOIN projects
                    ON ( content.content_id = projects.content_id 
                         AND content.content_type = 'project' ) 
        LEFT OUTER JOIN videos 
                    ON ( content.content_id = articles.content_id 
                         AND content.content_type = 'video' ) 
      WHERE (content.content_id IN (".implode(",",$new_array).")) AND content.author_id = users.u_id order by FIELD(content.content_id,".implode(",",$new_array).")";
  $result = mysqli_query($con,$query);
if($result!=null && $result->num_rows>0){
    while( $contentrow = $mysqli_fetch_assoc($result){
      print_r($contentrow);
  }
}

---

$new_array是我正在查询数据库的内容ID。当我在phpmyadmin中获得正确的id值时，打印的$contentrow的content\u id字段为null。

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