Php Codeigniter form_验证未验证

我目前正在处理我的登录表单。昨天我登录时，即使凭据错误，它也会让我登录，因此我在我的模型中将此代码的

=

更改为

=

public function can_log_in() {

    $sql ="SELECT * FROM tbl_users WHERE USERNAME = ? AND PASSWORD = ?";
    $data1 = array(
        'USERNAME' => $this->input->post('USERNAME'),
        'PASSWORD' => $this->input->post('PASSWORD')
    );
    $query = $this->db->query($sql, $data1);

    if ($query->num_rows == 1) {
        return true;
    } else {
        return false;
    }
}

现在，即使凭据正确，它也不会登录。这是我的控制器：

public function loginValidate() {

    $this->load->library('form_validation');

    $this->form_validation->set_rules('USERNAME','Username','required|trim|callback_validateCreds');
    $this->form_validation->set_rules('PASSWORD','Password','required|trim');

    if ($this->form_validation->run() == FALSE) {
        $this->index();
    } else {
        $data = array(
            'USERNAME' => $this->input->post('USERNAME'),
            'is_logged_in' => 1
        );
        $this->session->set_userdata($data);

        redirect('login/adminIndex'); 
    }
}

public function validateCreds() {

    $this->load->library('form_validation');
    $this->load->model('login_model');

    if($this->login_model->can_log_in()) { // can_log_in() model
        return true;
    } else {
        $this->form_validation->set_message('validateCreds','Username and password did not match.');  //return message to validateCreds

        return false;
    }
}

---

在问题模型函数中靠近

if（$query->num\u rows==1）

如果（$query->num_rows（）==1），您可以这样更改

模型函数中的完整代码

public function can_log_in(){

$sql ="SELECT * FROM tbl_users WHERE USERNAME = ? AND PASSWORD = ?";
$data1 = array(
    'USERNAME' => $this->input->post('USERNAME'),
    'PASSWORD' => $this->input->post('PASSWORD')
    );

$this->db
$query = $this->db->query($sql, $data1);


if ($query->num_rows() == 1){

    return true;

}else{

    return false;
}

通常密码是加密的，你考虑过吗？是的。我刚刚取消了加密，这样我就可以更容易地发现是否有错误或信用是错误的。