Php 执行以下代码时不显示同意页

在执行下面的代码时，它没有询问“允许”/“拒绝”选项（同意页）。如果我使用gmail id登录，它将直接输入并显示用户信息。我不知道我想在这段代码中做什么，显示允许或拒绝谷歌同意页面

如果我注释“$client->setHttpClient（new GuzzleHttp\client（['verify'=>false]））这段代码，致命错误：未捕获异常“GuzzleHttp\exception\RequestException”，并显示消息“cURL error 60:SSL证书问题：无法获取本地颁发者证书”将引发错误。有人能帮我吗

<?php

    require_once __DIR__.'/google-api-php-client-master/vendor/autoload.php';
    const CLIENT_ID='';
    const CLIENT_SECRET='';
    const REDIRECT_URI ='http://localhost:81/oauth/';
    const SAMPLE_API_KEY='';
    session_start();

    $client=new Google_Client();
    $client->setClientId(CLIENT_ID);
    $client->setClientSecret(CLIENT_SECRET);
    $client->setRedirectUri(REDIRECT_URI);
    $client->setDeveloperKey(SAMPLE_API_KEY);
    $client->addScope("https://www.googleapis.com/auth/userinfo.email");

    $client->setHttpClient(new GuzzleHttp\Client(['verify'=>false]));



    $plus=new Google_Service_Plus($client);


    if(isset($_REQUEST['logout']))
    {
        session_unset();
        unset($_SESSION['access_token']);
        //$client->revokeToken($_SESSION['access_token']);
    }

    if(isset($_GET['code']))
    {
        $client->authenticate($_GET['code']);
        $_SESSION['access_token']=$client->getAccessToken();
        $redirect='http://'.$_SERVER['HTTP_HOST'].$_SERVER['PHP_SELF'];
        header('Location:'.filter_var($redirect,FILTER_SANITIZE_URL));
    }

    if(isset($_SESSION['access_token'])&&$_SESSION['access_token'])
    {
        $client->setAccessToken($_SESSION['access_token']);
        $me=$plus->people->get('me');

        $id=$me['id'];
        $name=$me['displayName'];
        $email=$me['emails'][0]['value'];
        $profile_image_url=$me['image']['url'];
        $cover_image_url=$me['cover']['coverPhoto']['url'];
        $profile_url=$me['url'];
    }

    else
    {
        $authUrl=$client->createAuthUrl();
    }
    ?>

    <div>
        <?php

            if(isset($authUrl)){

                echo "<a href='".$authUrl."'><button>Login</button></a>";            
            }
            else
            {
                print "Id:  {$id} <br>";
                print "Name : {$name} <br>";
                print "Email : {$email} <br>";

                echo "<a href='?logout'><button>Logout</button></a>";
            }
         ?>
    </div>