Php 当前会话中的用户名

我想在当前会话中添加用户名为的隐藏字段。用户名位于另一个名为User的实体中。如何解决

public function buildForm(FormBuilderInterface $builder, array $options)
{
    $builder
        ->add('title', TextType::class, array('required' => false))
        ->add('description', TextareaType::class, array(
            'required' => false,
            'attr' => array('style' => 'resize: none')))
        ->add('imageFile', FileType::class);
}



public function addPhotoAction(Request $request)
{
    $photo = new Photo();
    $user = $this->getUser()->getId();
    $form = $this->createForm(PhotoFormType::class, $photo);
    $form->handleRequest($request);

    if($form->isSubmitted() && $form->isValid()){

        $em = $this->getDoctrine()->getManager();
        $em->persist($photo);
        $em->flush();

        $this->addFlash('success', 'You\'ve shared a photo!');

        return $this->redirectToRoute('homepage');
    }

    return $this->render('pages/addPhoto.html.twig', [
        'photoForm' => $form->createView(),
        'user' => $user
    ]);
}

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如何将userId添加到$builder？id（用户表）必须在addedBy（照片表）中。我必须做一个亲戚

您可以将数据推送到表单字段。若将隐藏字段添加到表单对象，它看起来像这些行

$form = $this->createForm(PhotoFormType::class, $photo);
$form->get('usernameField')->setData($this->getUser()->getUsername());

---

您可以将数据推送到表单字段。若将隐藏字段添加到表单对象，它看起来像这些行

$form = $this->createForm(PhotoFormType::class, $photo);
$form->get('usernameField')->setData($this->getUser()->getUsername());

---

您是否尝试从容器中获取用户？是否尝试从容器中获取用户？