Php使用json字符串中的duople quetes添加coma

我试过这个密码

foreach($comment as $cmd)
    {
        $dids=$cmd['qid'];
        $json = json_encode($dids);
    }   echo($json);

我的输出是这样的

"1""2"

如何在这些字符串之间添加逗号

我想要我的输出1,2

---

请帮助我

您需要手动添加逗号

foreach($comment as $cmd) {
    $dids=$cmd['qid'];
    $json = json_encode($dids) . ",";
}

谢谢

---

Amit

您需要手动添加逗号

foreach($comment as $cmd) {
    $dids=$cmd['qid'];
    $json = json_encode($dids) . ",";
}

谢谢

---

Amit

这应该可以做到：

<?php
    $dids = array();
    foreach($comment as $cmd) {
        $dids[]=$cmd['qid'];
    }
    $json = json_encode($dids);
    echo($json);
?>

---

这应该可以做到：

<?php
    $dids = array();
    foreach($comment as $cmd) {
        $dids[]=$cmd['qid'];
    }
    $json = json_encode($dids);
    echo($json);
?>

请改用此代码：

    foreach($comment as $cmd){
    $dids=$cmd['qid'];
    $json = json_encode($dids).",";
}echo substr($json,0,strlen($json)-1);

请改用此代码：

    foreach($comment as $cmd){
    $dids=$cmd['qid'];
    $json = json_encode($dids).",";
}echo substr($json,0,strlen($json)-1);

它在这里工作

  foreach($comment as $cmd) {
        $dids=$cmd['qid'];
        $dids=$dids.",";
        $json = json_encode($dids);
    }

它在这里工作

  foreach($comment as $cmd) {
        $dids=$cmd['qid'];
        $dids=$dids.",";
        $json = json_encode($dids);
    }

---

答案来了，但如何删除最后一个逗号我的输出，如1,2，使用@A.C.Manikandan答案来了，但如何删除最后一个逗号我的输出，如1,2，使用@A.C.Manikandan