Php 语法错误,意外';其他';(其他)
我用MySQL数据库编写了一个基本的登录系统,我遇到了这个问题。有解决办法吗?这也是一个活生生的问题。如果您转到OcelaRealms.com/proxy并尝试登录,则会出现此错误,“解析错误:语法错误,C:\xampp\htdocs\proxy\login.php第40行出现意外的'else'(T_else)” 这是我的代码:Php 语法错误,意外';其他';(其他),php,mysql,html,Php,Mysql,Html,我用MySQL数据库编写了一个基本的登录系统,我遇到了这个问题。有解决办法吗?这也是一个活生生的问题。如果您转到OcelaRealms.com/proxy并尝试登录,则会出现此错误,“解析错误:语法错误,C:\xampp\htdocs\proxy\login.php第40行出现意外的'else'(T_else)” 这是我的代码: <?php session_start(); $username = $_POST['username']; $password = $_POST['pass
<?php
session_start();
$username = $_POST['username'];
$password = $_POST['password'];
if ($username&&$password)
{
$connect = mysql_connect("192.168.1.19","root","xxx") or die ("Couldnt connect to MySQL database. Please contact Ocela at dylplum2002@gmail.com");
mysql_select_db("proxy") or die ("Couldn't find database. Please contact Ocela at dylplum2002@gmail.com");
$query = mysql_query("SELECT * FROM users WHERE username='$username'");
$numrows = mysql_num_rows($query);
if($numrows !=0)
{
while ($row = mysql_fetch_assoc($query))
{
$dbusername = $row['username'];
$dbpassword = $row['password'];
{
if ($username==$dbusername&&$password==$dbpassword)
{
echo "Login succesful. <a href='/proxy/index.php'>Click here to enter the Premium Proxy.</a>";
$_SESSION['username']=$dbusername;
}
else
echo "Incorrect password.";
}
else
die "That login doesnt exist. To get an account please contact Dylan.";
}
else
die ("Please enter a username and password.");
?>
您已经在while中添加了{
,并且您还忘记为您的if($numrows!=0)
添加}
在问题中发布您的代码。为每个代码行缩进4个空格,或使用编辑框顶部的{}按钮。第27行缺少if
语句。
<?php
session_start();
$username = $_POST['username'];
$password = $_POST['password'];
if ($username&&$password)
{
$connect = mysql_connect("192.168.1.19","root","xxx") or die ("Couldnt connect to MySQL database. Please contact Ocela at dylplum2002@gmail.com");
mysql_select_db("proxy") or die ("Couldn't find database. Please contact Ocela at dylplum2002@gmail.com");
$query = mysql_query("SELECT * FROM users WHERE username='$username'");
$numrows = mysql_num_rows($query);
if($numrows !=0)
{
while ($row = mysql_fetch_assoc($query))
{
$dbusername = $row['username'];
$dbpassword = $row['password'];
if ($username==$dbusername&&$password==$dbpassword)
{
echo "Login succesful. <a href='/proxy/index.php'>Click here to enter the Premium Proxy.</a>";
$_SESSION['username']=$dbusername;
}
else
echo "Incorrect password.";
}
}
else
die "That login doesnt exist. To get an account please contact Dylan.";
}
else
die ("Please enter a username and password.");
?>