Php 如何使用日期元素值按yyyy-mm对JSON数据进行分组?

Php 如何使用日期元素值按yyyy-mm对JSON数据进行分组?,php,arrays,json,date,grouping,Php,Arrays,Json,Date,Grouping,我有一些JSON数据,我想按月份重新组合,并最终使用PHP将每个组放入HTML无序列表中 当前的JSON: [ { "title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.", "date": "2017-03-15" }, { "title": "Lorem ipsum dolor sit amet, consectetur adipiscing e

我有一些JSON数据,我想按月份重新组合,并最终使用PHP将每个组放入HTML无序列表中

当前的JSON:

[
   {
        "title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
        "date": "2017-03-15"
    },
    {
        "title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
        "date": "2017-03-08"
    },
    {
        "title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
        "date": "2017-02-25"
    },
    {
        "title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
        "date": "2017-02-14"
    },
    {
        "title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
        "date": "2016-12-25"
    },
    {
        "title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
        "date": "2016-01-06"
    }
]
我认为下面的结构是我需要能够在无序列表中逐月反映出来的。请随意提出其他建议

{
    "2017-03": [
        {
            "title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
            "date": "2017-03-15"
        },
        {
            "title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
            "date": "2017-03-08"
        }
    ],
    "2017-02": [
        {
            "title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
            "date": "2017-02-25"
        },
        {
            "title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
            "date": "2017-02-14"
        }
    ],
    "2016-12": [
        {
            "title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
            "date": "2016-12-25"
        }
    ],
    "2016-01": [
        {
            "title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
            "date": "2016-01-06"
        }
    ]
}
希望这能奏效

$string='[
    {
        "title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
        "date": "2017-03-15"
    },
    {
        "title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
        "date": "2017-03-08"
    },
    {
        "title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
        "date": "2017-02-25"
    },
    {
        "title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
        "date": "2017-02-14"
    },
    {
        "title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
        "date": "2016-12-25"
    },
    {
        "title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
        "date": "2016-01-06"
    }
]';
$array=array();
$result=array();
$array=  json_decode($string,true);
foreach($array as $value)
{
    $key=explode("-", $value["date"]);
    unset($key[2]);
    $key=implode("-", $key);
    $result[$key][]=$value;
}
echo json_encode($result,JSON_PRETTY_PRINT);
希望这能奏效

$string='[
    {
        "title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
        "date": "2017-03-15"
    },
    {
        "title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
        "date": "2017-03-08"
    },
    {
        "title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
        "date": "2017-02-25"
    },
    {
        "title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
        "date": "2017-02-14"
    },
    {
        "title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
        "date": "2016-12-25"
    },
    {
        "title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
        "date": "2016-01-06"
    }
]';
$array=array();
$result=array();
$array=  json_decode($string,true);
foreach($array as $value)
{
    $key=explode("-", $value["date"]);
    unset($key[2]);
    $key=implode("-", $key);
    $result[$key][]=$value;
}
echo json_encode($result,JSON_PRETTY_PRINT);
这应该有助于:

<?php
$json = '[{
    "title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
    "date": "2017-03-15"
}, {
    "title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
    "date": "2017-03-08"
}, {
    "title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
    "date": "2017-02-25"
}, {
    "title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
    "date": "2017-02-14"
}, {
    "title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
    "date": "2016-12-25"
}, {
    "title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
    "date": "2016-01-06"
}]';

$json_decode_array = json_decode($json, true);

$result_set = [];

foreach ($json_decode_array as $key => $value) {
    $new_key = explode("-", $value["date"]);
    $result_set_key = $new_key[0] . '-' . $new_key[1];
    $result_set[$result_set_key][] = $value;
}

print_r(json_encode($result_set,JSON_PRETTY_PRINT));
这应该有帮助:

<?php
$json = '[{
    "title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
    "date": "2017-03-15"
}, {
    "title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
    "date": "2017-03-08"
}, {
    "title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
    "date": "2017-02-25"
}, {
    "title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
    "date": "2017-02-14"
}, {
    "title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
    "date": "2016-12-25"
}, {
    "title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
    "date": "2016-01-06"
}]';

$json_decode_array = json_decode($json, true);

$result_set = [];

foreach ($json_decode_array as $key => $value) {
    $new_key = explode("-", $value["date"]);
    $result_set_key = $new_key[0] . '-' . $new_key[1];
    $result_set[$result_set_key][] = $value;
}

print_r(json_encode($result_set,JSON_PRETTY_PRINT));

有几种方法可以做到这一点:

输入:

$json='[
    {"title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
     "date": "2017-03-15"},
    {"title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
     "date": "2017-03-08"},
    {"title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
     "date": "2017-02-25"},
    {"title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
     "date": "2017-02-14"},
    {"title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
     "date": "2016-12-25"},
    {"title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
     "date": "2016-01-06"}
]';
方法:()一个干净、快速的foreach循环

$array=json_decode($json,true);
foreach($array as $a){
    $result[substr($a['date'],0,7)][]=$a;  // truncate the dates before assigning as keys
}
echo json_encode($result,JSON_PRETTY_PRINT);

substr()
专门为子字符串提取而设计时,只将生成的元素作为新的键插入日期
explode()
是非常愚蠢的。

有几种方法可以做到这一点:

输入:

$json='[
    {"title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
     "date": "2017-03-15"},
    {"title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
     "date": "2017-03-08"},
    {"title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
     "date": "2017-02-25"},
    {"title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
     "date": "2017-02-14"},
    {"title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
     "date": "2016-12-25"},
    {"title": "Lorem ipsum dolor sit amet, consectetur adipiscing elit.",
     "date": "2016-01-06"}
]';
方法:()一个干净、快速的foreach循环

$array=json_decode($json,true);
foreach($array as $a){
    $result[substr($a['date'],0,7)][]=$a;  // truncate the dates before assigning as keys
}
echo json_encode($result,JSON_PRETTY_PRINT);

substr()
专门为子字符串提取而设计时,
explode()
只插入生成的元素作为新键的日期是非常愚蠢的。

您有不必要的逗号
在json示例数据中,您有不必要的逗号
在json示例数据中,这正是我想要的,谢谢。否决票一定是因为太简单了。@l3fty否决票是因为您提供了自己的代码的绝对0,并且几乎要求其他人为您做所有的工作。@Dimi因为我完全不知道如何按照我的要求去做。老实说,我一直在想,我必须将日期与当前日期进行比较,然后在每一行中循环。我曾想过把它贴出来,但我并没有用完全错误的代码让读者更加困惑,只是问了一个精确的问题。这不是stackoverflow的作用吗?我没有看到任何规则规定我必须提供示例代码。@l3fty我个人从不否决任何事情/任何人(仍然没有批评家徽章),但一般来说,任何没有任何代码的问题都会被视为家庭作业问题,因此被大多数人忽略。尝试链接一些您尝试过的东西,或者粘贴一些损坏的代码。这正是我想要的,谢谢。否决票一定是因为太简单了。@l3fty否决票是因为您提供了自己的代码的绝对0,并且几乎要求其他人为您做所有的工作。@Dimi因为我完全不知道如何按照我的要求去做。老实说,我一直在想,我必须将日期与当前日期进行比较,然后在每一行中循环。我曾想过把它贴出来,但我并没有用完全错误的代码让读者更加困惑,只是问了一个精确的问题。这不是stackoverflow的作用吗?我没有看到任何规则规定我必须提供示例代码。@l3fty我个人从不否决任何事情/任何人(仍然没有批评家徽章),但一般来说,任何没有任何代码的问题都会被视为家庭作业问题,因此被大多数人忽略。尝试链接您尝试过的一些内容,或者粘贴一些损坏的代码。