Php Symfony爬虫从foreach中的getted childs获取子节点？

我和你一起工作

XML看起来像：

<Tours>
    <Tour id="1">
        <Termins>
            <Termin>
            ...

但我想找到这样的方法来使用爬虫程序：（主要的一点是没有来自“top”的选择器，但来自元素witch，它已经在foreach中了）

此时，当您通过

爬虫

时，您将得到一个

DOMNode

数组。然后可以为该子文档创建新的爬网程序

foreach ($crawler->filter('tour') as $tour) {
    $tourCrawler = new Crawler($tour);
    $tourCrawler->attr('id'); // 1...
    foreach ($tourCrawler->filter('termin') as $termin) {
        // Access nodes or create further crawlers
    } 
}

        foreach ($crawler->children() as $tour) {
            foreach($tour->first('Termins')->children() as $termin)

foreach ($crawler->filter('tour') as $tour) {
    $tourCrawler = new Crawler($tour);
    $tourCrawler->attr('id'); // 1...
    foreach ($tourCrawler->filter('termin') as $termin) {
        // Access nodes or create further crawlers
    } 
}