Php 错误:在laravel中使用Ajax Post方法更新表单时

Php 错误:在laravel中使用Ajax Post方法更新表单时,php,laravel,laravel-5.4,Php,Laravel,Laravel 5.4,我正在尝试更新我的Laravel表单,同时更新除文件字段以外的其他字段。我正在使用hasfile()检查此Laravel表单,但失败 如果我更新了文件上传,那么条件工作正常,唯一的问题是我在更新其他表单字段时没有更新文件 这里是我的控制器页面: public function update(Request $request, $id) { $this->validate($request,[ 'design_no'=>'required',

我正在尝试更新我的Laravel表单,同时更新除
文件
字段以外的其他字段。我正在使用
hasfile()
检查此Laravel表单,但失败

如果我更新了文件上传,那么条件工作正常,唯一的问题是我在更新其他表单字段时没有更新文件

这里是我的控制器页面:

public function update(Request $request, $id)
{

    $this->validate($request,[
        'design_no'=>'required',
        'design_image'=>'image|nullable|max:1999'
    ]);
            // Handle file Upload
     if ($request->hasFile('design_image')) {
        // Get filename with image 
            $filenameWithex=$request->file('design_image');
        // Get just file name
             $filename=$_FILES['design_image']['name'];
            // $filename=pathinfo($filenameWithex,PATHINFO_FILENAME);
        // Get just ex 
            // $extension=pathinfo($filenameWithex,PATHINFO_EXTENSION);
        // File Name To Store
            $fileNameToStore=$filename;
            $path=$request->file('design_image')->storeAs('public/images',$fileNameToStore);
    }else{
        $fileNameToStore='noimage.jpg';
    }
design::where('design_no',$id)->update([
           'desg_1' => $request->input('desg_1'),
            'design_image'=> $fileNameToStore,
            'desg_2' => $request->input('desg_2'),
            'desg_3' => $request->input('desg_3'),
            'desg_4' => $request->input('desg_4'),
            'desg_5' => $request->input('desg_5'),
            'desg_6' => $request->input('desg_6') 
]);
    $design->save();
    return '1';
}  
以下是我的Ajax调用:

    $('.submit').click(function(){
            $.ajaxSetup({
                headers: {
                        'X-CSRF-TOKEN': $('meta[name="csrf-token"]').attr('content')
                    }
            });
        var form = $('form')[0];
        var update = new FormData(form);
        var id =$('.designNo').val();
     $.ajax({
        type:"POST",
          url:"/design_update/"+id,
            processData: false,  // Important!
            contentType: false,
            cache: false,
          data:update,
          success:function(results){
            if (results==1) {
                $("#result").html("Upadated Successfully");
              }else{
                $('#error').html(results);
                }
            }
        }); 
    }); 

首先,您需要像这样验证您的文件

$this->validate($request,[
        'design_no'=>'required',
        'design_image'=>'nullable|image|mimes:jpg,png,jpeg|max:1999'
    ]);
if ($request->hasFile('design_image')) {
        // Get filename with image 
            $filenameWithex=$request->file('design_image');
        // Get just file name
             $filename=$_FILES['design_image']['name'];
            // $filename=pathinfo($filenameWithex,PATHINFO_FILENAME);
        // Get just ex 
            // $extension=pathinfo($filenameWithex,PATHINFO_EXTENSION);
        // File Name To Store
            $fileNameToStore=$filename;
            $path=$request->file('design_image')->storeAs('public/images',$fileNameToStore);

    design::where('design_no',$id)->update([
            'desg_1' => $request->input('desg_1'),
            'design_image'=> $fileNameToStore,
            'desg_2' => $request->input('desg_2'),
            'desg_3' => $request->input('desg_3'),
            'desg_4' => $request->input('desg_4'),
            'desg_5' => $request->input('desg_5'),
            'desg_6' => $request->input('desg_6') 
     ]);
}else{   // ignore design_image when you don't need to update that
    design::where('design_no',$id)->update([
            'desg_1' => $request->input('desg_1'),
            'desg_2' => $request->input('desg_2'),
            'desg_3' => $request->input('desg_3'),
            'desg_4' => $request->input('desg_4'),
            'desg_5' => $request->input('desg_5'),
            'desg_6' => $request->input('desg_6') 
     ]);
}
然后,您需要获取您正在更新的记录(如果您已经有这些记录),然后忽略此步骤

$designData = design::where('design_no',$id)->first();
现在,您需要检查变量
$fileNameToStore
是否有
noImage.jpg
意味着您没有在这里更新图像,在这种情况下,您需要更新并保持上次上载的文件完整,否则请像这样更新图像文件

design::where('design_no',$id)->update([
           'desg_1' => $request->input('desg_1'),
            'design_image'=> ($fileNameToStore != 'noimage.jpg') ? $fileNameToStore : $designData->design_image,
            'desg_2' => $request->input('desg_2'),
            'desg_3' => $request->input('desg_3'),
            'desg_4' => $request->input('desg_4'),
            'desg_5' => $request->input('desg_5'),
            'desg_6' => $request->input('desg_6') 
]);
替代方法

您也可以在这里做两个update语句来保持它的整洁

$this->validate($request,[
        'design_no'=>'required',
        'design_image'=>'nullable|image|mimes:jpg,png,jpeg|max:1999'
    ]);
if ($request->hasFile('design_image')) {
        // Get filename with image 
            $filenameWithex=$request->file('design_image');
        // Get just file name
             $filename=$_FILES['design_image']['name'];
            // $filename=pathinfo($filenameWithex,PATHINFO_FILENAME);
        // Get just ex 
            // $extension=pathinfo($filenameWithex,PATHINFO_EXTENSION);
        // File Name To Store
            $fileNameToStore=$filename;
            $path=$request->file('design_image')->storeAs('public/images',$fileNameToStore);

    design::where('design_no',$id)->update([
            'desg_1' => $request->input('desg_1'),
            'design_image'=> $fileNameToStore,
            'desg_2' => $request->input('desg_2'),
            'desg_3' => $request->input('desg_3'),
            'desg_4' => $request->input('desg_4'),
            'desg_5' => $request->input('desg_5'),
            'desg_6' => $request->input('desg_6') 
     ]);
}else{   // ignore design_image when you don't need to update that
    design::where('design_no',$id)->update([
            'desg_1' => $request->input('desg_1'),
            'desg_2' => $request->input('desg_2'),
            'desg_3' => $request->input('desg_3'),
            'desg_4' => $request->input('desg_4'),
            'desg_5' => $request->input('desg_5'),
            'desg_6' => $request->input('desg_6') 
     ]);
}

$request->all()
里面有什么?检查我的answer@aldrin27我不明白我的意思是,
$request
变量的值是多少。你得到解决方案了吗?很抱歉,晚了一点,我使用了似乎适合我的替代方法,但我不知道如果你能解释meno prob是否是最佳实践!好吧,这取决于你,如果你关心代码行,那么第一个更好,如果你不是,那么第二个适合你显然如果你正在使用,否则第二个更好!