从html表单收集数据的PHP脚本

我编写了一个php脚本，用于从html表单收集表单数据。下面是代码。我认为这是我缺少的简单的东西，我的php经验是有限的

欢迎提供任何帮助/建议。如果您编辑代码，请尽量具体，以便我可以看到错误所在

"\nComments:\n".$comments. ;
<?php
$error = "\n Please review the information you provided, there seems to be a problem" ;
$email1 = 'root@centos6.labform.localdomain' ;
$to = "$email1";
$from = $_POST['email'];
$name = "$firstname $lastname";
$headers = "From: $email \n";
$subject = 'Lab Systems Request Form';

// we now create the email

$message = array();
$firstname = $_POST['firstname'] ;
$lastname = $_POST['lastname'] ;
$extnumber = $_POST['extnumber'] ;
$department = $_POST['department'] ;
$email = $_POST['email'] ;
$type = $_POST['type'] ;
$systems = $_POST['systems'] ;
$comments = $_POST['comments'] ;


$body = "We have received the following information from $name:\n\nHere are the details:\n"
"\nFirstName:\n".$firstname.
"\nLastName:\n".$lastname.
"\nExtNumber:\n".$extnumber.
"\nDepartment:\n".$department.
"\nEmail:\n".$email.
"\nFormFactor:\n".$type.
"\nSystemType:\n".$systems.
//$body ="We have received the following information from $name:\n\n";
//"Here are the details:\n " ;
//"FirstName: $firstname \n" ;
//"LastName: $lastname \n" ;
//"ExtNumber: $extnumber \n" ;
//"Department: $department \n" ;
//"Email: $email \n" ;
//"FormFactor: $type \n" ;
//"SystemType: $systems \n" ;
//"Comments: $comments \n" ;

// now we send the email and redirect to thankyou.html if all ok
$send = mail( $to,$from,$headers,$subject,$body );
//print "$to,$subject,$body,$headers";

if($send)
 {header( "Location: thankyou.html" );}
 else
 {print "We encountered an error sending your mail, please notify directly
$email1 or $email2"; }

?>

此外，当我出于某种原因打印所有数据时，它会在每行前放置一个1:-S，并按相反顺序收集数据 非常感谢！ 斯托尼思

嗨，谢谢你的回复。我已经编辑了代码。我补充了你的建议。代码运行正常，它重定向到thankyou.html，但如果我在每个：\nFirstName:\n.$firstname……的开头添加print，则电子邮件正文为空。。。。。。。然后我可以看到收集的示例数据，但我得到的是：Date:Thu，2012年4月19日15:54:22+0100 IST From:Apache To:root@centos6.labform.localdomain主题：root@centos6.labform.localdomain实验室系统申请表来源：且未收集其他数据

以下是html表单： 下面是collection.php：

邮件函数中的参数顺序错误。发件人地址应位于标题中。看看能不能搞定它。

安东尼奥

您需要更详细地描述出现了什么问题，以及我们需要查看表单的所有代码，尽管听起来脚本正在运行

在Lex所说的基础上，$body变量有一个。最后是不应该出现的情况：

$body = "We have received the following information from $name:\n\nHere are the details:\n"
"\nFirstName:\n".$firstname.
"\nLastName:\n".$lastname.
"\nExtNumber:\n".$extnumber.
"\nDepartment:\n".$department.
"\nEmail:\n".$email.
"\nFormFactor:\n".$type.
"\nSystemType:\n".$systems.
"\nComments:\n".$comments. ;

应该是：

$body = "We have received the following information from $name:\n\nHere are the      details:\n"
"\nFirstName:\n".$firstname.
"\nLastName:\n".$lastname.
"\nExtNumber:\n".$extnumber.
"\nDepartment:\n".$department.
"\nEmail:\n".$email.
"\nFormFactor:\n".$type.
"\nSystemType:\n".$systems.
"\nComments:\n".$comments ;

---

您看到了什么错误消息，或者您期望的是什么/没有发生？正如Richard指出的，这将由于语法错误而失败。这是一个好主意，检查一些至少运行前张贴！我认为指定该字符串的更好方法是只使用一个开始和结束分隔符，并按字面意思将其放在换行符中。这样就省去了大量的开/关和连接。哈弗，这就是您的意思：$body=我们从.$name收到了以下信息：$n\n详情如下：\n\nFirstName:\n$firstname\nLastName:\n$lastname\nExtNumber:\n$extnumber\n部门：\n$department\nEmail:\n$email\nFormFactor:\n$type\n系统类型：\n$systems\n注释：\n$comments；现在几乎所有工作都已删除：$message=$body，并已更改$body=。。。。。。至$message=。。。。。。现在，所有表单数据都已收集，但“$from”显示为空白。是否有任何建议？谢谢，$email变量有数据吗？