Php 带有JOIN Doctrine2和Symfony2的DQL
你好,我有两张桌子:产品和存货。他们有很多种关系,看起来是这样的: 股票:Php 带有JOIN Doctrine2和Symfony2的DQL,php,mysql,symfony,join,doctrine-orm,Php,Mysql,Symfony,Join,Doctrine Orm,你好,我有两张桌子:产品和存货。他们有很多种关系,看起来是这样的: 股票: +------------+--------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +------------+--------------+------+-----+---------+----------------+ |
+------------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+------------+--------------+------+-----+---------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| stock_name | varchar(255) | NO | | NULL | |
| address | varchar(255) | NO | | NULL | |
+------------+--------------+------+-----+---------+----------------+
产品:
+----------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+----------+--------------+------+-----+---------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| stock_id | int(11) | YES | MUL | NULL | |
| name | varchar(255) | NO | | NULL | |
| delivery | varchar(255) | NO | | NULL | |
+----------+--------------+------+-----+---------+----------------+
实体
class Products
{
/**
* @ORM\Id
* @ORM\GeneratedValue
* @ORM\Column(type="integer")
*/
private $id;
/**
* @ORM\Column(type="string")
*/
private $name;
/**
* @ORM\Column(type="string")
*/
private $delivery;
/**
* @ORM\ManyToOne(targetEntity="Stock", inversedBy="products")
* @ORM\JoinColumn(nullable=true)
*/
private $stock;
/**
* @return mixed
*/
public function getName()
{
return $this->name;
}
/**
* @param mixed $name
*/
public function setName($name)
{
$this->name = $name;
}
/**
* @return mixed
*/
public function getDelivery()
{
return $this->delivery;
}
/**
* @param mixed $delivery
*/
public function setDelivery($delivery)
{
$this->delivery = $delivery;
}
/**
* @return mixed
*/
public function getStock()
{
return $this->stock;
}
/**
* @param mixed $stock
*/
public function setStock(Stock $stock)
{
$this->stock = $stock;
}
/**
* @return mixed
*/
public function getId()
{
return $this->id;
}
}
class Stock
{
/**
* @ORM\Id
* @ORM\GeneratedValue
* @ORM\Column(type="integer")
*/
private $id;
/**
* @ORM\Column(type="string")
*/
private $stock_name;
/**
* @ORM\Column(type="string")
*/
private $address;
/**
* @ORM\OneToMany(
* targetEntity="Products",
* mappedBy="stock",
* orphanRemoval=true
* )
*/
private $products;
/**
* @return mixed
*/
public function getStockName()
{
return $this->stock_name;
}
/**
* @param mixed $stock_name
*/
public function setStockName($stock_name)
{
$this->stock_name = $stock_name;
}
/**
* @return mixed
*/
public function getAddress()
{
return $this->address;
}
/**
* @param mixed $address
*/
public function setAddress($address)
{
$this->address = $address;
}
/**
* @return mixed
*/
public function getId()
{
return $this->id;
}
/**
* @return mixed
*/
public function getProducts()
{
return $this->products;
}
/**
* @param mixed $products
*/
public function setProducts($products)
{
$this->products = $products;
}
}
我需要一个sql,它可以为我提供与stock id 1关联的所有交付地址,并在stock表的id 1下只向该数组添加一个stock地址。该数组应该如下所示:
Array (
[0] => Stock Address
[1] => delivery1
[2] => delivery2
[3] => delivery3
)
我尝试使用此语句,但它给出了数组中的乘法股票地址和数组:
$qb = $this->getEntityManager()->createQuery(
"SELECT o.delivery , p.address
FROM AppBundle:Products o
JOIN o.stock p
WHERE o.stock =1
");
return $qb->getScalarResult();
这项声明的结果是:
Array (
[0] => Array (
[delivery] => Spoon str, USA
[address] => Wall street 1, USA
)
[1] => Array (
[delivery] => Lincoln street, USA
[address] => Wall street 1, USA
)
)
您将无法通过一条DQL语句直接检索所需的数组。原因是您实际上希望在示例中获取的四行来自两个不同的列 所以你需要以某种方式处理结果。例如,您可以将代码段更改为:
$qb = $this->getEntityManager()->createQuery(
"SELECT o.delivery , p.address
FROM AppBundle:Products o
JOIN o.stock p
WHERE o.stock = 1
");
$result = $qb->getScalarResult();
return array_merge([$result[0]['address']], array_column($result, 'delivery'));
因此,您将地址作为要返回的数组的第一个元素,只添加所有结果的delivery列,并将其添加。您谈论的是原则。实体定义在哪里?