Php MySQL：两条记录对一条记录

我有一张这样的桌子

id conversation_id messageable_id
 1               1              3 <--
 2               1              5
 3               2              7
 4               2              3 <--
 5               3              7
 6               3              9

如何生成查询

提前感谢。

您可以使用MySQL 8.0中提供的lead：

select *
from (
    select
        conversation_id,
        messageable_id sender_id,
        lead(messageable_id) over(partition by conversation_id order by id) receiver_id
    from mytable
) t
where sender_id = 3

select *
from (
    select
        conversation_id,
        messageable_id sender_id,
        lead(messageable_id) over(partition by conversation_id order by id) receiver_id
    from mytable
) t
where sender_id = 3