Php 成功调用ajax时无法从数据库获取结果
我是一个初学者，在PHP代码中无法通过ajax调用从数据库中获得结果 下面是带有ajax调用的示例php代码Php 成功调用ajax时无法从数据库获取结果,php,jquery,ajax,Php,Jquery,Ajax,我是一个初学者，在PHP代码中无法通过ajax调用从数据库中获得结果 下面是带有ajax调用的示例php代码 <script> $('.input').on('click',function(e){ e.preventDefault(); $.ajax({ method:'POST', url:'',
<script>
$('.input').on('click',function(e){
e.preventDefault();
$.ajax({
method:'POST',
url:'',
data:{data_username:$('#username').val(),
data_lastname:$('#lastname').val()},
success:function(data){
var x =JSON.parse(data);
for(var index in x){ //here my error
console.log(x[index].username);
}
}
,error:function(){
alert("failed!!!!!");
}
});
});
</script>
查看您发布的代码表明您正在将ajax请求发送到同一页面，这让我认为您收到的错误是因为有其他HTML内容与您想要的JSON内容混搭在一起。为了防止这种情况发生，请在开始发送ajax查询响应并确保脚本在发送数据时完成之前，将请求发送到其他页面或使用ob_clean。也许下面的内容会有所帮助 还有一个拼写错误$usernmae应该是$username
你有什么错误？。就在var x=JSON.parsedata之后；这一行您可以使用console.logx并查找您收到的错误消息。您是否将ajax请求发送到同一页面并在响应中收到错误？我附加了您的代码而不是我的代码，并且没有在控制台中打印任何内容，但实现了错误：函数{alertfailed！！！！；}好的-我不使用jQuery，所以我为这个错误道歉-删除contentType:'application/json；charset=utf-8'，并且tryi'很抱歉代码没有与我一起运行，请帮助我
<?php
$use_live_db=false; # set to true to try running sql queries against db
if( isset( $_POST['data_username'], $_POST['data_lastname'] ) ){
/*
when sending ajax to the same page you must ensure that ONLY the
data you want is allowd to be sent - so using `ob_clean()` will
discard any previously generated content from appearing in the
output
*/
ob_clean();
/*
I appreciate this is probably for testing but this is
simply yielding data you already know...
*/
$username=$_POST['data_username'];
$lastname=$_POST['data_lastname'];
$sql='SELECT username, lastname FROM login where username=:one AND lastname=:two';
$results=array(
'username' => $username,
'lastname' => $lastname,
'sql' => $sql
);
if( $use_live_db ){
/* !!! CHANGE THIS TO THE APPROPRIATE FILE FOR YOUR SYSTEM !!! */
require '/path/to/db-pdo.php';
$results=array();
$stmt=$db->prepare( $sql );
if( $stmt ){
# think it should be bindParam rather than bindparam!
$stmt->bindParam(':one',$username,PDO::PARAM_STR);
$stmt->bindParam(':two',$lastname,PDO::PARAM_STR);
$stmt->execute();
while( $row=$stmt->fetch() ){
$results[]=$row;
}
}else{
exit('error: failed to prepare sql query');
}
}
/*
Similarly to using `ob_clean()` you must prevent the remainder of
the current page appearing as part of the ajax response -
so use `exit` or `die`
*/
header('Content-Type: application/json');
exit( json_encode( $results ) );
}
?>
<!DOCTYPE html>
<html lang='en'>
<head>
<meta charset='utf-8' />
<title>jQuery & AJAX - POST request to PHP script to interrogate db</title>
<script src='//code.jquery.com/jquery-latest.js'></script>
</head>
<body>
<form>
<input type='text' id='username' name='username' value='mike' />
<input type='text' id='lastname' name='lastname' value='hunt' />
<input type='button' class='input' value='OK' />
</form>
<script>
$('.input').on('click',function(e){
e.preventDefault();
$.ajax({
method:'POST',
url:location.href,
/*
If you set the dataType
properties jQuery automagically ensures
the response is in the correct format- JSON
*/
dataType: 'json',
data:{
data_username:$('#username').val(),
data_lastname:$('#lastname').val()
},
success:function( json ){
console.info('username: %s\nlastname: %s\nSQL: %s', json.username, json.lastname, json.sql )
alert('ok')
},
error:function(){
alert('failed!!!!!');
}
});
});
</script>
</body>
</html>