将三列sql映射到php数组

我有一个MySQL表，其中有四列：location\u id、location\u name、address、city

我需要做两个下拉列表，其中第一个下拉列表是城市名称。因此，如果有10个同名城市，下拉列表中应该只有1个城市。选择该城市后，相应的位置名称应出现在下一个下拉列表中-位置名称。选择位置名称下拉列表后，将显示其相应的地址

我的逻辑之一是： 从数据库中选择所有不同的城市。通过另一个查询，选择所有信息。

查询：

从位置选择不同的（城市）

这会给我所有不同的城市名称

从位置选择*

所有必需的数据

制作一个数组，其中key是城市名称，位置细节作为数组。像这样的

 Array
(
    [0] => stdClass Object
        (
            [location_id] => 27
            [location_name] => ANSND
            [address] => some street 1
            [city] => NYC
        )

    [1] => stdClass Object
        (
            [location_id] => 809
            [location_name] => ANBC
            [address] => some street 1
            [city] => NYC
        )

    [2] => stdClass Object
        (
            [location_id] => 810
            [location_name] => dasddsdss
            [address] => some street 1
            [city] => Calif
        )

    [3] => stdClass Object
        (
            [location_id] => 811
            [location_name] => testing 6 feb
            [address] => some street 1
            [city] => Calif
        )

)

如何在PHP中实现这一点

Array
(
    [NYC] => Array
        (
            [0] => stdClass Object
                (
                    [location_id] => 27
                    [location_name] => ANSND
                    [city] => NYC
                    [address] => some street 1 

                )

            [1] => stdClass Object
                (
                    [location_id] => 809
                    [location_name] => ANBC
                    [city] => NYC
                    [address] => fsff
                )

        )

    [Calif] => Array
        (
            [0] => stdClass Object
                (
                    [location_id] => 810
                    [location_name] => dasddsdss
                    [city] => Calif
                    [address] => some street 1
                )

            [1] => stdClass Object
                (
                    [location_id] => 811
                    [location_name] => testing 6 feb
                    [city] => Calif
                    [address] => some street 1
                )

        )

)


您的疑问是什么？您的问题是什么？请详细解释。@Prakash编辑了该问题。您能显示表“位置”的10个数据吗？地址字段在哪里？请尝试以下答案
<?php 
    $results = array(); // it will be your resulted array

    $data_locations = array(); // lets say it is your data list of location table

    foreach( $data_locations as $location )
    {
        $results[$location->city][] = array(
            'location_name' =>$location->location_name; 
            'address' =>$location->address; 
        )
    }

    echo "<pre>"; print_r( $results ); die;
?>