Php 获取日期时间格式之间的持续时间

如何在php中以小时-分钟-秒格式获取开始日期和结束日期之间的持续时间

$start_date=2012-03-23 11:58:14  and $end_date=2012-03-24 11:54:29

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此功能将帮助您

function datediff($interval, $datefrom, $dateto, $using_timestamps = false) {
 /*
  $interval can be:
  yyyy - Number of full years
  q - Number of full quarters
  m - Number of full months
  y - Difference between day numbers
   (eg 1st Jan 2004 is "1", the first day. 2nd Feb 2003 is "33". The datediff is "-32".)
  d - Number of full days
  w - Number of full weekdays
  ww - Number of full weeks
  h - Number of full hours
  n - Number of full minutes
  s - Number of full seconds (default)
 */

将这些字符串设置为最新格式

将这些日期转换为毫秒

开始日期

根据结果计算h:mm:ss

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使用

DateTime

类：

$start_date = new DateTime('2012-03-23 11:58:14');
$end_date = new DateTime('2012-03-24 11:54:29');

$dd = date_diff($end_date, $start_date);

要获得小时数，请使用

$dd->h

，分钟-

$dd->i

，秒-

$dd->s

echo "Hours = $dd->h, Minutes = $dd->i, Seconds = $dd->s";

我会的

$start_time = strtotime($start_date);
$end_time = strtotime($end_date);
$difference = $end_time - $start_time;
echo date('H:i:s', $difference);

编辑

我错误地假设时差小于一天，因此如果时差大于一天，您将只看到小时：分钟：秒，这可能不是您想要的（如果是，请忽略此）

所以我现在想

$seconds = $difference % 60;            //seconds
$difference = floor($difference / 60);
$min = $difference % 60;              // min
$difference = floor($difference / 60);
$hours = $difference;  //hours
echo "$hours : $min : $seconds";

抱歉进行了更正

请在此处查看它的工作情况：

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在这里，你没有考虑时间区为什么要考虑时区，他正在计算差异，这将总是返回“23：56:15”，即使$STATIONDATE改为“2012-03-22:11:58:14”（一天前），我们需要像年、月、日、小时和秒的格式，我可以计算H:mm：SS？

$start_date="2012-03-22 11:58:14";
$end_date="2012-03-24 11:54:29";

$start_time = strtotime($start_date);
$end_time = strtotime($end_date);
$difference = $end_time - $start_time;

echo sprintf("%02d%s%02d%s%02d", floor($difference/3600), ':', ($difference/60)%60, ':', $difference%60); // outputs 47:56:15