Php 如何使用fetch assoc和fetch array

我只想知道谁正在登录系统，所以我想知道用户登录的位置，并把他们带到他们的工作地点。我不知道如何使用fetch assoc或fetch array提前感谢您的帮助。。希望你们能理解，抱歉

$email = $_POST['email'];
$password = $_POST['password'];
$tableName = "";
$position = "";

function login($tableName)
{
    global $connect, $email, $password;
    $query = "SELECT * FROM " . $tableName . " WHERE email=? AND password=? LIMIT 1";
    $statement = mysqli_prepare($connect, $query);
    mysqli_stmt_bind_param($statement, "ss", $email, $password);
    mysqli_stmt_execute($statement);
    mysqli_stmt_store_result($statement);
    $count = mysqli_stmt_num_rows($statement);
    mysqli_stmt_close($statement);
    $row = mysqli_fetch_array($statement);
    $data = mysqli_fetch_assoc($statement);    
    return ($count == 1);

}

if (login('tbl_users')) {

    $_SESSION['user'] = $row['email'];

    header('Location:../index.html');

} else if (login('tbl_gramusers')) {
    $row['position'];
    echo $row;

    //   header('Location:../stocks_index.html');
    //header('Location:../admin.html');     
} else {
    echo 'Wrong Username or password!';
}

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一旦到达

返回（$count==1）行将不会执行询问您，但是如何在那里获取位置列和特定数据？您不应该使用
mysql\u
函数。另外，为什么要混合使用
mysql\uu
和
mysqli\u
函数？我也没看到，我只是从我的旧作品中复制过来的