Php AJAX POST JSON数组Javascript不是JQUERY
在这个屏幕截图中,一个JSON数组通过AJAX传递给PHP,而没有一个POST主体。我正在使用此代码来实现它:Php AJAX POST JSON数组Javascript不是JQUERY,php,javascript,json,post,xmlhttprequest,Php,Javascript,Json,Post,Xmlhttprequest,在这个屏幕截图中,一个JSON数组通过AJAX传递给PHP,而没有一个POST主体。我正在使用此代码来实现它: with(x=new XMLHttpRequest()) open("POST", "http://myweb/api/mobile/v1/jobeventadd?key=cfff"), setRequestHeader("Content-Type", "application/x-www-form-urlencoded"), send("%7B%0A%22SessionID%22%3
with(x=new XMLHttpRequest()) open("POST", "http://myweb/api/mobile/v1/jobeventadd?key=cfff"), setRequestHeader("Content-Type", "application/x-www-form-urlencoded"), send("%7B%0A%22SessionID%22%3A%22hn0oqa0u687avsrnev6f5t2nh7%22%2C%0A%22ObjectID%22%3A%226460%22%2C%0A%22ItemName%22%3A%22UologiciPhone%20test%20event%22%2C%0A%22ActivityFrom%22%3A%2201-01-2013%2012%3A00%3A00%22%0A%7D");
但它不起作用。如何通过XMLHttpRequest实现这一点无JQUERY请在成功状态后使用获取响应,然后将数据存储在自定义标题中以解决帖子正文的问题:
with(new XMLHttpRequest)
{
open("POST",{},true);
setRequestHeader("Foo", "Bar");
send("");
onreadystatechange = handler;
}
function handler(event)
{
!!event.target && !!event.target.readyState && event.target.readyState === 4 && ( console.log(event) );
}
参考资料
with(new XMLHttpRequest)
{
open("POST","http://google.com",true);
send("hello=world&no=yes");
onreadystatechange = function(){};
}