Php 从iPhone发布图像时出现奇怪问题

Php 从iPhone发布图像时出现奇怪问题,php,iphone,ios,file-upload,Php,Iphone,Ios,File Upload,我在从iPhone上传图像时遇到了一个非常奇怪的问题。当我从iPhone上传图像时,会创建服务器上的图像,但大小为0 我使用了许多PHP函数从字节接收图像,但都是徒劳的,我从iPhone以二进制形式(多部分内容类型)发送图像到httppost 下面给出了所有代码。下面是我使用过的各种PHP方法,但它们都不起作用 $id=rand() ; // for image name //=====================1st method========================

我在从iPhone上传图像时遇到了一个非常奇怪的问题。当我从iPhone上传图像时,会创建服务器上的图像,但大小为0

我使用了许多PHP函数从字节接收图像,但都是徒劳的,我从iPhone以二进制形式(多部分内容类型)发送图像到httppost

下面给出了所有代码。下面是我使用过的各种PHP方法,但它们都不起作用

$id=rand() ;  // for image name

//=====================1st method========================   
if(isset($_REQUEST['image_string'])) {      
    $imgData =@$_REQUEST['image_string'];

    header('Content-Type:image/jpg; charset=utf-8');     

    $file = fopen("new_arrivals_img/".$id.".jpg", 'wb');
    fwrite($file, $binary);   
    fclose($file);   
}    

//========================2nd method=====================

if(isset($_REQUEST['image_string'])) {
     $imgData =$_REQUEST['image_string'];
    $im = imagecreatefromstring($imgData);

    $src="new_arrivals_img/".$id.".png";
    imagepng($im,$src);
}


//=======================3rd method==================

if(isset($_REQUEST['image_string'])) {    
    $target_path = "new_arrivals_img/";
    $target_path = $target_path.basename($_FILES['image_string']['name']);  

    move_uploaded_file($_FILES['image_string']['tmp_name'], $target_path);              
}

//===================4th method ===========

if(isset($_REQUEST['image_string'])) {    
    $imageString = file_get_contents($_REQUEST['image_string']);
    $save = file_put_contents("new_arrivals_img/".$id.".png",$_REQUEST['image_string']);   
}   

//==========================5th method =================

if(isset($_REQUEST['image_string'])) {   
    copy($_REQUEST['image_string'], "new_arrivals_img/".$id.".png");   
}   

//======6th method =========================================


if(isset($_REQUEST['image_string'])) {      
    $url = $_REQUEST['image_string'];
    $dir = "new_arrivals_img/";
    $lfile = fopen($dir . basename($url), "w");

    $ch = curl_init();
    curl_setopt($ch, CURLOPT_URL, $url);
    curl_setopt($ch, CURLOPT_HEADER, 0);
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
    curl_setopt($ch, CURLOPT_USERAGENT, 'Mozilla/4.0 (compatible; MSIE 7.0; Windows NT 5.1)');
    curl_setopt($ch, CURLOPT_FILE, $lfile);
    curl_exec($ch);
    fclose($lfile);
    curl_close($ch);
}
iOs代码如下所示:

//image_string3 is parameter in which imagedata1 passed and server url is // http://192.95.48.44/image_binary/index.php



    NSData *imageData1 = UIImageJPEGRepresentation(myImage,0.2);     //change Image to NSData

        if (imageData1 != nil)
        {

            NSString *urlString = @"http://192.95.48.44/image_binary/index.php";

            NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init];
            [request setURL:[NSURL URLWithString:urlString]];
            [request setHTTPMethod:@"POST"];

            NSString *boundary = [NSString stringWithString:@"---------------------------14737809831466499882746641449"];
            NSString *contentType = [NSString stringWithFormat:@"multipart/form-data; boundary=%@",boundary];
            [request addValue:contentType forHTTPHeaderField: @"Content-Type"];

            NSMutableData *body = [NSMutableData data];



            [body appendData:[[NSString stringWithFormat:@"\r\n--%@\r\n",boundary] dataUsingEncoding:NSUTF8StringEncoding]];
            [body appendData:[[NSString stringWithString:@"Content-Disposition: form-data; name=\"image_string\"; filename=\"test123.jpg\"\r\n"] dataUsingEncoding:NSUTF8StringEncoding]];

            [body appendData:[[NSString stringWithString:@"Content-Type: application/octet-stream\r\n\r\n"] dataUsingEncoding:NSUTF8StringEncoding]];
            [body appendData:[NSData dataWithData:imageData1]];
            [body appendData:[[NSString stringWithFormat:@"\r\n--%@--\r\n",boundary] dataUsingEncoding:NSUTF8StringEncoding]];
            // setting the body of the post to the reqeust
            [request setHTTPBody:body];

            NSLog(@"body %@",body);
            NSLog(@"request %@",request);
            // now lets make the connection to the web
            NSData *returnData = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil];
            NSString *returnString = [[NSString alloc] initWithData:returnData encoding:NSUTF8StringEncoding];
            NSLog(@"returning strin %@",returnString);
            NSLog(@"finish");

        }

我认为你在Objective-C中的作用是正确的。但是,我认为您使用的PHP端方法是不正确的。这是我使用的,它工作得非常完美:

function uploadPicture(){

    if ($_FILES["file"]["name"] == "noimage.jpg"){
        return "noimage.jpg";
    }

    $uploadLocation = "failed";

    $allowedExts = array("jpg", "jpeg", "gif", "png");

    $extension = end(explode(".", $_FILES["file"]["name"]));
    echo "file size" . ($_FILES["file"]["size"] / 1024) . "KB";

    if (($_FILES["file"]["size"] < 500000) && in_array($extension, $allowedExts)){

        if ($_FILES["file"]["error"] > 0) {
            echo "Return Code: " . $_FILES["file"]["error"] . "<br />";
        } else {
            echo "Upload: " . $_FILES["file"]["name"] . "<br />";
            echo "Type: " . $_FILES["file"]["type"] . "<br />";
            echo "Size: " . ($_FILES["file"]["size"] / 1024) . " Kb<br />";
            echo "Temp file: " . $_FILES["file"]["tmp_name"] . "<br />";

            if (file_exists("upload/" . $_FILES["file"]["name"])) {
                echo $_FILES["file"]["name"] . " already exists. ";
            } else {
                move_uploaded_file($_FILES["file"]["tmp_name"],
                    "upload/" . $_FILES["file"]["name"]);
                echo "Stored in: " . "upload/" . $_FILES["file"]["name"];
                $uploadLocation = "upload/" . $_FILES["file"]["name"];
            }
        }
    } else {
        echo "invalid file";
    }

    return $uploadLocation;
}

我认为你在Objective-C中的作用是正确的。但是,我认为您使用的PHP端方法是不正确的。这是我使用的,它工作得非常完美:

function uploadPicture(){

    if ($_FILES["file"]["name"] == "noimage.jpg"){
        return "noimage.jpg";
    }

    $uploadLocation = "failed";

    $allowedExts = array("jpg", "jpeg", "gif", "png");

    $extension = end(explode(".", $_FILES["file"]["name"]));
    echo "file size" . ($_FILES["file"]["size"] / 1024) . "KB";

    if (($_FILES["file"]["size"] < 500000) && in_array($extension, $allowedExts)){

        if ($_FILES["file"]["error"] > 0) {
            echo "Return Code: " . $_FILES["file"]["error"] . "<br />";
        } else {
            echo "Upload: " . $_FILES["file"]["name"] . "<br />";
            echo "Type: " . $_FILES["file"]["type"] . "<br />";
            echo "Size: " . ($_FILES["file"]["size"] / 1024) . " Kb<br />";
            echo "Temp file: " . $_FILES["file"]["tmp_name"] . "<br />";

            if (file_exists("upload/" . $_FILES["file"]["name"])) {
                echo $_FILES["file"]["name"] . " already exists. ";
            } else {
                move_uploaded_file($_FILES["file"]["tmp_name"],
                    "upload/" . $_FILES["file"]["name"]);
                echo "Stored in: " . "upload/" . $_FILES["file"]["name"];
                $uploadLocation = "upload/" . $_FILES["file"]["name"];
            }
        }
    } else {
        echo "invalid file";
    }

    return $uploadLocation;
}

在这个问题上花了两天时间后,我终于找到了解决方案,这是我的服务器中的问题,它不允许我动态或通过编程创建图像

虽然我已经给了我创建图像的文件夹完整的权限(读、写、更新或777)


我刚刚更换了服务器,它工作得很好,我使用的代码和AdamG提供的代码都对我有效。

在这个问题上花了两天时间后,我终于找到了解决方案,是我的服务器出现了问题,不允许我动态或通过编程创建图像

虽然我已经给了我创建图像的文件夹完整的权限(读、写、更新或777)


我刚更换了服务器,它工作得很好,我使用的代码和AdamG提供的代码都对我起作用。

看起来你去过五金店,把看到的每一个厨房水槽都买了下来,然后把它们都扔到墙上,看哪一个粘在墙上……看起来你去过五金店,把看到的每一个厨房水槽都买下来,然后把它们都扔到墙上,看看哪一个粘在墙上……嗨,谢谢你的回答,我得到了解决方案,让我贴在这里。嗨,谢谢你的回答,我得到了解决方案,让我贴在这里。我应该想到这一点。我刚开始做这件事的时候也遇到过这种情况,我应该想到这一点。这也发生在我刚开始做这件事的时候。