Php 从iPhone发布图像时出现奇怪问题
我在从iPhone上传图像时遇到了一个非常奇怪的问题。当我从iPhone上传图像时,会创建服务器上的图像,但大小为0 我使用了许多PHP函数从字节接收图像,但都是徒劳的,我从iPhone以二进制形式(多部分内容类型)发送图像到httppost 下面给出了所有代码。下面是我使用过的各种PHP方法,但它们都不起作用Php 从iPhone发布图像时出现奇怪问题,php,iphone,ios,file-upload,Php,Iphone,Ios,File Upload,我在从iPhone上传图像时遇到了一个非常奇怪的问题。当我从iPhone上传图像时,会创建服务器上的图像,但大小为0 我使用了许多PHP函数从字节接收图像,但都是徒劳的,我从iPhone以二进制形式(多部分内容类型)发送图像到httppost 下面给出了所有代码。下面是我使用过的各种PHP方法,但它们都不起作用 $id=rand() ; // for image name //=====================1st method========================
$id=rand() ; // for image name
//=====================1st method========================
if(isset($_REQUEST['image_string'])) {
$imgData =@$_REQUEST['image_string'];
header('Content-Type:image/jpg; charset=utf-8');
$file = fopen("new_arrivals_img/".$id.".jpg", 'wb');
fwrite($file, $binary);
fclose($file);
}
//========================2nd method=====================
if(isset($_REQUEST['image_string'])) {
$imgData =$_REQUEST['image_string'];
$im = imagecreatefromstring($imgData);
$src="new_arrivals_img/".$id.".png";
imagepng($im,$src);
}
//=======================3rd method==================
if(isset($_REQUEST['image_string'])) {
$target_path = "new_arrivals_img/";
$target_path = $target_path.basename($_FILES['image_string']['name']);
move_uploaded_file($_FILES['image_string']['tmp_name'], $target_path);
}
//===================4th method ===========
if(isset($_REQUEST['image_string'])) {
$imageString = file_get_contents($_REQUEST['image_string']);
$save = file_put_contents("new_arrivals_img/".$id.".png",$_REQUEST['image_string']);
}
//==========================5th method =================
if(isset($_REQUEST['image_string'])) {
copy($_REQUEST['image_string'], "new_arrivals_img/".$id.".png");
}
//======6th method =========================================
if(isset($_REQUEST['image_string'])) {
$url = $_REQUEST['image_string'];
$dir = "new_arrivals_img/";
$lfile = fopen($dir . basename($url), "w");
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_USERAGENT, 'Mozilla/4.0 (compatible; MSIE 7.0; Windows NT 5.1)');
curl_setopt($ch, CURLOPT_FILE, $lfile);
curl_exec($ch);
fclose($lfile);
curl_close($ch);
}
iOs代码如下所示:
//image_string3 is parameter in which imagedata1 passed and server url is // http://192.95.48.44/image_binary/index.php
NSData *imageData1 = UIImageJPEGRepresentation(myImage,0.2); //change Image to NSData
if (imageData1 != nil)
{
NSString *urlString = @"http://192.95.48.44/image_binary/index.php";
NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init];
[request setURL:[NSURL URLWithString:urlString]];
[request setHTTPMethod:@"POST"];
NSString *boundary = [NSString stringWithString:@"---------------------------14737809831466499882746641449"];
NSString *contentType = [NSString stringWithFormat:@"multipart/form-data; boundary=%@",boundary];
[request addValue:contentType forHTTPHeaderField: @"Content-Type"];
NSMutableData *body = [NSMutableData data];
[body appendData:[[NSString stringWithFormat:@"\r\n--%@\r\n",boundary] dataUsingEncoding:NSUTF8StringEncoding]];
[body appendData:[[NSString stringWithString:@"Content-Disposition: form-data; name=\"image_string\"; filename=\"test123.jpg\"\r\n"] dataUsingEncoding:NSUTF8StringEncoding]];
[body appendData:[[NSString stringWithString:@"Content-Type: application/octet-stream\r\n\r\n"] dataUsingEncoding:NSUTF8StringEncoding]];
[body appendData:[NSData dataWithData:imageData1]];
[body appendData:[[NSString stringWithFormat:@"\r\n--%@--\r\n",boundary] dataUsingEncoding:NSUTF8StringEncoding]];
// setting the body of the post to the reqeust
[request setHTTPBody:body];
NSLog(@"body %@",body);
NSLog(@"request %@",request);
// now lets make the connection to the web
NSData *returnData = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil];
NSString *returnString = [[NSString alloc] initWithData:returnData encoding:NSUTF8StringEncoding];
NSLog(@"returning strin %@",returnString);
NSLog(@"finish");
}
我认为你在Objective-C中的作用是正确的。但是,我认为您使用的PHP端方法是不正确的。这是我使用的,它工作得非常完美:
function uploadPicture(){
if ($_FILES["file"]["name"] == "noimage.jpg"){
return "noimage.jpg";
}
$uploadLocation = "failed";
$allowedExts = array("jpg", "jpeg", "gif", "png");
$extension = end(explode(".", $_FILES["file"]["name"]));
echo "file size" . ($_FILES["file"]["size"] / 1024) . "KB";
if (($_FILES["file"]["size"] < 500000) && in_array($extension, $allowedExts)){
if ($_FILES["file"]["error"] > 0) {
echo "Return Code: " . $_FILES["file"]["error"] . "<br />";
} else {
echo "Upload: " . $_FILES["file"]["name"] . "<br />";
echo "Type: " . $_FILES["file"]["type"] . "<br />";
echo "Size: " . ($_FILES["file"]["size"] / 1024) . " Kb<br />";
echo "Temp file: " . $_FILES["file"]["tmp_name"] . "<br />";
if (file_exists("upload/" . $_FILES["file"]["name"])) {
echo $_FILES["file"]["name"] . " already exists. ";
} else {
move_uploaded_file($_FILES["file"]["tmp_name"],
"upload/" . $_FILES["file"]["name"]);
echo "Stored in: " . "upload/" . $_FILES["file"]["name"];
$uploadLocation = "upload/" . $_FILES["file"]["name"];
}
}
} else {
echo "invalid file";
}
return $uploadLocation;
}
我认为你在Objective-C中的作用是正确的。但是,我认为您使用的PHP端方法是不正确的。这是我使用的,它工作得非常完美:
function uploadPicture(){
if ($_FILES["file"]["name"] == "noimage.jpg"){
return "noimage.jpg";
}
$uploadLocation = "failed";
$allowedExts = array("jpg", "jpeg", "gif", "png");
$extension = end(explode(".", $_FILES["file"]["name"]));
echo "file size" . ($_FILES["file"]["size"] / 1024) . "KB";
if (($_FILES["file"]["size"] < 500000) && in_array($extension, $allowedExts)){
if ($_FILES["file"]["error"] > 0) {
echo "Return Code: " . $_FILES["file"]["error"] . "<br />";
} else {
echo "Upload: " . $_FILES["file"]["name"] . "<br />";
echo "Type: " . $_FILES["file"]["type"] . "<br />";
echo "Size: " . ($_FILES["file"]["size"] / 1024) . " Kb<br />";
echo "Temp file: " . $_FILES["file"]["tmp_name"] . "<br />";
if (file_exists("upload/" . $_FILES["file"]["name"])) {
echo $_FILES["file"]["name"] . " already exists. ";
} else {
move_uploaded_file($_FILES["file"]["tmp_name"],
"upload/" . $_FILES["file"]["name"]);
echo "Stored in: " . "upload/" . $_FILES["file"]["name"];
$uploadLocation = "upload/" . $_FILES["file"]["name"];
}
}
} else {
echo "invalid file";
}
return $uploadLocation;
}
在这个问题上花了两天时间后,我终于找到了解决方案,这是我的服务器中的问题,它不允许我动态或通过编程创建图像 虽然我已经给了我创建图像的文件夹完整的权限(读、写、更新或777)
我刚刚更换了服务器,它工作得很好,我使用的代码和AdamG提供的代码都对我有效。在这个问题上花了两天时间后,我终于找到了解决方案,是我的服务器出现了问题,不允许我动态或通过编程创建图像 虽然我已经给了我创建图像的文件夹完整的权限(读、写、更新或777)
我刚更换了服务器,它工作得很好,我使用的代码和AdamG提供的代码都对我起作用。看起来你去过五金店,把看到的每一个厨房水槽都买了下来,然后把它们都扔到墙上,看哪一个粘在墙上……看起来你去过五金店,把看到的每一个厨房水槽都买下来,然后把它们都扔到墙上,看看哪一个粘在墙上……嗨,谢谢你的回答,我得到了解决方案,让我贴在这里。嗨,谢谢你的回答,我得到了解决方案,让我贴在这里。我应该想到这一点。我刚开始做这件事的时候也遇到过这种情况,我应该想到这一点。这也发生在我刚开始做这件事的时候。