Php Larvel：仅获取具有'；用户'；用户表中的角色

我有

用户、角色

表，其中每个

用户

都在

角色

表中附加了一个

角色

。我需要在我的

UserController

中获取

role\u user

中关联的角色名为“user”的所有用户（不包括管理员）

我现在有这个：

UserController:

class UserController extends Controller {

    public function index() {
        $users = User::all(); // Get here only users with role 'user' in role_user table

        return view( 'admin.users.index' )
            ->with( 'users', $users )
        ;
    }
}

创建用户表：

class CreateUsersTable extends Migration {

    public function up() {
        Schema::create('users', function (Blueprint $table) {
            $table->id();
            $table->string('email')->unique();
            $table->string('name');
            $table->string('last_name');
            $table->timestamp('email_verified_at')->nullable();
            $table->string('password');
            $table->rememberToken();
            $table->timestamps();
        });
    }
}

class CreateRolesTable extends Migration {

    public function up() {
        Schema::create('roles', function (Blueprint $table) {
            $table->id();
            $table->string('name')->unique();
            $table->string('description');
            $table->timestamps();
        });
    }
}

class CreateRoleUserTable extends Migration {

    public function up() {
        Schema::create('role_user', function (Blueprint $table) {
            $table->id();
            $table->string('user_id')->unique();
            $table->integer('role_id')->unsigned();
            $table->timestamps();
        });
    }
}

创建角色表：

class CreateUsersTable extends Migration {

    public function up() {
        Schema::create('users', function (Blueprint $table) {
            $table->id();
            $table->string('email')->unique();
            $table->string('name');
            $table->string('last_name');
            $table->timestamp('email_verified_at')->nullable();
            $table->string('password');
            $table->rememberToken();
            $table->timestamps();
        });
    }
}

class CreateRolesTable extends Migration {

    public function up() {
        Schema::create('roles', function (Blueprint $table) {
            $table->id();
            $table->string('name')->unique();
            $table->string('description');
            $table->timestamps();
        });
    }
}

class CreateRoleUserTable extends Migration {

    public function up() {
        Schema::create('role_user', function (Blueprint $table) {
            $table->id();
            $table->string('user_id')->unique();
            $table->integer('role_id')->unsigned();
            $table->timestamps();
        });
    }
}

创建角色用户表：

class CreateUsersTable extends Migration {

    public function up() {
        Schema::create('users', function (Blueprint $table) {
            $table->id();
            $table->string('email')->unique();
            $table->string('name');
            $table->string('last_name');
            $table->timestamp('email_verified_at')->nullable();
            $table->string('password');
            $table->rememberToken();
            $table->timestamps();
        });
    }
}

class CreateRolesTable extends Migration {

    public function up() {
        Schema::create('roles', function (Blueprint $table) {
            $table->id();
            $table->string('name')->unique();
            $table->string('description');
            $table->timestamps();
        });
    }
}

class CreateRoleUserTable extends Migration {

    public function up() {
        Schema::create('role_user', function (Blueprint $table) {
            $table->id();
            $table->string('user_id')->unique();
            $table->integer('role_id')->unsigned();
            $table->timestamps();
        });
    }
}

如何实现这一点？

在User.php模型中：

public function roles()
    {
        return $this->belongsToMany('App\Role');
    }

在控制器中：

$users = User::whereHas('roles' , function($q){
   $q->whereName('user');
})->get();

---

试试elequent而不是Great Thank<代码>$query->where（'name'，'user'）也有效。