将mysql数组结果分配给php变量

我正在尝试使用API向mysql表中的所有成员发送sms

我能够发送短信

但是只使用表中的第一行，而我希望sms被发送到表中的所有记录

我使用的代码如下所示：

$db = JFactory::getDbo();
$query = $db->getQuery(true);
$result = mysql_query("SELECT name,mobile FROM members");
if (!$result) {
echo 'Could not run query: ' . mysql_error();
exit;
}
$row = mysql_fetch_row($result);
$mobile=$row[1];
$name=$row[0];

$request = "";
$param['mobileno'] = "91". $mobile;
$param['message']  = "Dear $name (organisation name) wishes you a very very Happy Birthday";
$param['username'] = "username";
$param['password']  = "password";
$param['sendername'] = "sender";
foreach ($param as $key => $val ){$request .= $key . "=" . urlencode($val);    
$request .= "&";}$request = substr( $request, 0, strlen( $request ) - 1 );
$url = "http://smsapi" . $request;
$ch = curl_init($url);curl_setopt($ch, CURLOPT_URL, $url );
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true );
$result = curl_exec($ch);
var_dump($result);exit;
curl_close( $ch );

我已经根据答案中的建议修改了代码，但我仍然只得到第一行的结果

$db = JFactory::getDbo();
$query = $db->getQuery(true);
$result = mysql_query("SELECT name,mobile FROM members");
if (!$result) {
echo 'Could not run query: ' . mysql_error();
exit;
}
while($row = mysql_fetch_row($result)) {
$mobile=$row[1];
$name=$row[0];

$request = "";
$param['mobileno'] = "91". $mobile;
$param['message']  = "Dear $name (organisation name) wishes you a very very Happy Birthday";
$param['username'] = "username";
$param['password']  = "password";
$param['sendername'] = "sender";
foreach ($param as $key => $val ){$request .= $key . "=" . urlencode($val);    
$request .= "&";}$request = substr( $request, 0, strlen( $request ) - 1 );
$url = "http://smsapi" . $request;
$ch = curl_init($url);curl_setopt($ch, CURLOPT_URL, $url );
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true );
$result = curl_exec($ch);
var_dump($result);exit;
curl_close( $ch );
}

使用while（$row=mysql\u fetch\u row（$result））循环遍历行

$db = JFactory::getDbo();
$query = $db->getQuery(true);
$result = mysql_query("SELECT name,mobile FROM members");
if (!$result) {
echo 'Could not run query: ' . mysql_error();
exit;
}
while($row = mysql_fetch_row($result)) {
$mobile=$row[1];
$name=$row[0];

$request = "";
$param['mobileno'] = "91". $mobile;
$param['message']  = "Dear $name (organisation name) wishes you a very very Happy Birthday";
$param['username'] = "username";
$param['password']  = "password";
$param['sendername'] = "sender";
foreach ($param as $key => $val ){$request .= $key . "=" . urlencode($val);    
$request .= "&";}$request = substr( $request, 0, strlen( $request ) - 1 );
$url = "http://smsapi" . $request;
$ch = curl_init($url);curl_setopt($ch, CURLOPT_URL, $url );
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true );
$result = curl_exec($ch);
var_dump($result);exit;
curl_close( $ch );
}

---

您需要循环所有行

$db = JFactory::getDbo();
$query = $db->getQuery(true);
$result = mysql_query("SELECT name,mobile FROM members");
if (!$result) {
echo 'Could not run query: ' . mysql_error();
exit;
}
while($row = mysql_fetch_row($result)) {
$mobile=$row[1];
$name=$row[0];

$request = "";
$param['mobileno'] = "91". $mobile;
$param['message']  = "Dear $name (organisation name) wishes you a very very Happy Birthday";
$param['username'] = "username";
$param['password']  = "password";
$param['sendername'] = "sender";
foreach ($param as $key => $val ){$request .= $key . "=" . urlencode($val);    
$request .= "&";}$request = substr( $request, 0, strlen( $request ) - 1 );
$url = "http://smsapi" . $request;
$ch = curl_init($url);curl_setopt($ch, CURLOPT_URL, $url );
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true );
$result = curl_exec($ch);
var_dump($result);exit;
curl_close( $ch );
}

比如：

while($row = mysql_fetch_row($result)) { .... }

---

另外，php mysql扩展已被弃用，请查看mysqli或pdo。

您使用的是mysql_fetch_row，据我所知，它只返回一行（如果找到）。考虑使用MySqLyFutChyFALL代替

我已经修改了上面的代码，但是我仍然只得到第一行的结果。实际上代码工作正常。我认为var_dump（$result）；出口只显示了一行结果，这给我的印象是代码并没有在所有行中循环。谢谢