Php SQL在中仅选择ID中的1行

如何在sql请求中为每个ID仅获取一张照片

我的画廊桌子：

+----+----------+
| id | name     |
+----+----------+
| 1  | gallery1 |
| 2  | gallery2 |
| 3  | gallery3 |
+----+----------+

和照片表：

+----+------------+------------+
| id |    name    | gallery_id |
+----+------------+------------+
|  1 | photo1.jpg |      1     |
|  2 | photo2.jpg |      1     |
|  3 | photo3.jpg |      2     |
|  4 | photo4.jpg |      3     |
|  5 | photo5.jpg |      3     |
|  6 | photo6.jpg |      3     |
+----+------------+------------+

我使用MySQL 我从gallery sql中选择了我的图库，然后我想从photos sql中为每一行获取一张照片。你能帮我怎么做吗

foreach($this->gallery as $val){
        $this->arr_id = $this->arr_id.$val['id'].',';
      }
      $this->arr_id = trim($this->arr_id, ',');
      echo $this->arr_id; (4,3,2,1)

---

您需要使用一些聚合函数和group by按类别过滤单个照片，如下所示：

SELECT min(id) as photo_id FROM photos GROUP BY gallery_id

现在，您可以利用此信息为每个图库获取一张照片：

SELECT 
    *
FROM
    photos
WHERE
    id IN (SELECT 
            MIN(id) AS photo_id
        FROM
            photos
        GROUP BY gallery_id)

您也可以使用

JOIN

而不是

WHERE IN

：

SELECT 
    *
FROM
    photos
        JOIN
    (SELECT 
        MIN(id) AS photo_id
    FROM
        photos
    GROUP BY gallery_id) single ON (photos.id = single.photo_id)

如果还需要库名，

将上面的
与
库
表也连接起来：

SELECT 
    *
FROM
    photos
        JOIN
    gallery ON (photos.gallery_id = gallery.id)
        JOIN
    (SELECT 
        MIN(id) AS photo_id
    FROM
        photos
    GROUP BY gallery_id) single ON (photos.id = single.photo_id)

随机照片

SELECT *
FROM gallery G
INNER JOIN 
    (
        SELECT id AS photo_id, gallery_id  
        FROM photos
        ORDER BY RAND()
        LIMIT 1
    ) p ON G.id = p.gallery_id

第一张照片：

SELECT *
FROM gallery G
INNER JOIN 
    (
        SELECT MIN(id) AS photo_id, gallery_id  
        FROM photos
        GROUP BY gallery_id
    ) p ON G.id = p.gallery_id

最后一张照片：

SELECT *
FROM gallery G
INNER JOIN 
    (
        SELECT MAX(id) AS photo_id, gallery_id  
        FROM photos
        GROUP BY gallery_id
    ) p ON G.id = p.gallery_id  

你想要什么还不清楚，请解释清楚。是否要为每个库仅选择一张照片，或其他内容？展示你现有的照片是的，我只想为每个画廊拍一张照片如果有多个潜在的候选人，那么你的标准是什么来决定在输出中要哪一张？哪一张。一个？？？？第一个仅返回一张照片用于一个图库@草莓
LIMIT 1
不是吗？我想OP希望每个画廊有一张照片——就像你的其他查询一样。