Php 如何从两个表中选择信息?
我试图从两个表中获取数据:Php 如何从两个表中选择信息?,php,mysqli,Php,Mysqli,我试图从两个表中获取数据: $con = getDbConnect(); $edit = $_GET['edit']; if (mysqli_connect_errno($con)) { "Failed to connect to MySQL: " . mysqli_connect_error(); } else { $result = mysqli_query($con, "SELECT * FROM admininfo where email='" . $edit . "'
$con = getDbConnect();
$edit = $_GET['edit'];
if (mysqli_connect_errno($con)) {
"Failed to connect to MySQL: " . mysqli_connect_error();
} else {
$result = mysqli_query($con, "SELECT * FROM admininfo where email='" . $edit . "'");
$results = mysqli_query($con, "SELECT * FROM adminaccount where email='" . $edit . "'");
while ($admininfo = mysqli_fetch_array($result, $results)) {
无论从多少个表中选择,都使用单个查询,例如
SELECT a.*, b.* FROM table1 a, table2 b where a.id = ? AND b.id = ?
然后从结果中获取所需内容,并查看相应的结果
-当然,不要使用。从阅读手册开始:看看你的代码有多错误